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What is the Vertex Form for a Quadratic Equation ?
The vertex form for a quadratic function is as follows: f(x) = a(x - h) 2 + k The graph of this function Is a parabola whose axis of symmetry is the vertical line x = h, and whose vertex is the point (h, k).
Remember: If a > 0 then the graph opens upward.
If a < 0 then the graph opens downward.
In order to use the vertex form to find the vertex, you must know how to complete the square.Here's an example of what I mean by completing the square:
Question: Find the vertex of the graph of
f(x) = x2 - 4x + 5
Answer: In order to do this, we must write the function in vertex form.f(x) = x2 -4x + 5y = x2 - 4x + 5y - 5 = x2 - 4xy - 5 + 4 = x2 -4x + 4y - 1 = (x -2) 2 y = (x - 2)2 + 1f(x) = (x-2)2 +1H kThe vertex of the parabola is then (h, k) = (2, 1)
Find and classify the equilibrium solutions of the subsequent differential equation. y' = y 2 - y - 6 Solution The equilibrium solutions are to such differential equati
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Calculate the area and perimeter of a parallelogram: Calculate the area and perimeter of a parallelogram with base (b) = 4´, height (h) = 3´, a = 5´ and b = 4´. Be sure to in
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Find out the area of the region bounded by y = 2 x 2 + 10 and y = 4 x + 16 . Solution In this case the intersection points (that we'll required eventually) are not going t
Solve by factorization X 2 +(a/a+b + a+b/a)x+1 = 0 X 2 +(a/a+b + a+b/a)x+1 => X 2 +(a/a+b x a+b/ax + a/a+b .a+b/a) => X[x+a/a+b] +a+b/a[a+a*a+b]= 0 => X= -a
Determine an actual explicit solution to y′ = t/y; y(2) = -1. Solution : We already identify by the previous illustration that an implicit solution to this IVP is y 2 = t 2 -
Definition 1. We say that f(x) consist an absolute (or global) maximum at x = c if f ( x ) ≤ f (c ) for every x in the domain we are working on. 2. We say that at x = c ,
Advantages of decision trees 1. This clearly brings out implicit calculations and assumptions for all to see question and revise 2. This is simple to understand Disadvan
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