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Q. A beam of electrons travelling with a speed of 4 X 107 ms-1 is projected normal to a magnetic field of B = 10-3 Wb m-2. What is the path of the beam in the magnetic field?
Solution: Since the electrons are released usually to the magnetic field the electrons travel in a circular path.
∴ Bev = mv2/ r
r = mv/Be = 9.11 X 10-31 X 4 X 107 / 10-3 X 1.6 X 10 -19
Radius of the path r = 0.2275 m.
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