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What is the maximum number of fragments that can result from a single IP Datagram? Explain.
To fragment a datagram for transmission across a network, a router utilizes the network MTU that is Maximum Transmission Unit and the datagram header size to compute the maximum amount of data which can be sent in each fragment and number of fragment which will be required. The router than creates the fragments. A datagram cannot be larger than the MTU of a network over that this is sent. If a fragment ultimately reaches another network which has a smaller MTU then fragment is further separated in smaller fragments. IP does not differentiate between sub fragments and original fragments. Therefore the maximum number of fragments from a single datagram will depend upon size of datagram and MTU of the networks over that this is sent along its path.
Explain how a shift register can be used as a ring counter giving the wave forms at the output of the flipflops. Ans: Shift Register as a Ring Counter: A Ring Counter is a
Loop Level At this stage, following loop iterations are candidates for parallel execution. Though, data dependencies among subsequent iterations can restrict parallel execution
Multiple Instruction and Multiple Data stream (MIMD) In this association, multiple control units and multiple processing elements are prepared as in MISD. But the discrepancy i
The LOOP-ENDLOOP on extract datasets can be used without any kind of errors False. It causes runtime errors.
Level of a node The root is at level zero and the level of the node is 1 more than the level of its parent
Q. Hardware required for superscalar processing? For applying superscalar processing a number of special hardware should be offered that is discussed below: • The necessity
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reate a directory "Unix" under your home directory. Command(s): ………………………………………….
Unions allow the same area of memory to be accessed as different data types. The insurance example above would not work. Unions are useful (often in embedded programming) when i
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