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As x tends to zero the value of 1/x tends to either ∞ or -∞. In this situation we will not be sure about the exact value of 1/x. As a result we will not be sure about the exact/approaching value of sin(1/x). We cant say anything about the value of sine function unless we know the angle and in this question we are not sure about the angle as at infinity it can take any value. We will be sure that the value of sin(1/x) will lie in [-1, 1] but not sure about a unique value. As in limits, it exists only when we get a unique value. Therefore we will say that the limit does not exist.
sin 51+cos 81
Find the probability of having 53 Sundays in (i) a leap year (ii) a non leap year (Ans:2/7 , 1/7 ) Ans: An ordinary year has 365 da
how to find inverse of matrix
Advantages And Limitations Of Game Theory Advantage Game theory assists us to learn how to approach and understand a conflict condition and to develop the decision making
1,500cm m
compare: 643,251: 633,512: 633,893. The answer is 633,512.
important trigonometric formulas for class 10th CBSC board
Solve following 4e 1+3 x - 9e 5-2 x = 0 . Solution Here the first step is to get one exponential on every side & then we'll divide both sides by one of them (that doesn'
what are the factors af 34?
Limit sin(1/x) when x tends to 0 is not definedCan be proved simply by multiplying and dividing by x then xsin(1/x)/x becomes 1/x as xsin(1/x)or for that matter sin(1/x)/1/x = 1 and limit reduces to 1/x which doesnt exist Also the proof can be that when x approcashes 0 from positive side 1/x tends to positive infinty and limit (right0 becomes sin(infinity) but when from left side 1/x tends to negative infinty so limit becomes -sin(infinit) which both can never b equal. so limit doesnt exist
Limit sin(1/x) when x tends to 0 is not definedCan be proved simply by multiplying and dividing by x then xsin(1/x)/x becomes 1/x as xsin(1/x)or for that matter sin(1/x)/1/x = 1 and limit reduces to 1/x which doesnt exist Also the proof can be that when x approcashes 0 from positive side 1/x tends to positive infinty and limit (right0 becomes sin(infinity) but when from left side 1/x tends to negative infinty so limit becomes -sin(infinit) which both can never b equal.
so limit doesnt exist
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