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As x tends to zero the value of 1/x tends to either ∞ or -∞. In this situation we will not be sure about the exact value of 1/x. As a result we will not be sure about the exact/approaching value of sin(1/x). We cant say anything about the value of sine function unless we know the angle and in this question we are not sure about the angle as at infinity it can take any value. We will be sure that the value of sin(1/x) will lie in [-1, 1] but not sure about a unique value. As in limits, it exists only when we get a unique value. Therefore we will say that the limit does not exist.
Volumes for Solid of Revolution Before deriving the formula for it we must probably first describe just what a solid of revolution is. To find a solid of revolution we start o
help me on thus subject pls
Frequently, tests that yield abnormal results are repeated for confirmation. What is the probability that for a usual person a test will be at least 1.5 times as high as the upper
in a triangle angle a is 70 and angle b is 50 what is angle c.
Let D = 1 denotes the event that an adult male has a particular disease. In the population, it is known that the probability of having this disease is 20 percent, i.e., Pr (D = 1)
how to convert multiple integral into polar form and change the limits of itegration
Solve sin (α /7) =0 . Solution By Using a unit circle it isn't too difficult to see that the solutions to this equation are, α /7 = 0 + 2 ? n ⇒ α = 14 ? n
Q. Define Combined Functions? Ans. We are often interested in functions which combine a trigonometric function with another type of function. For example, y = x + sinx wi
write a computer program that will implement Steffensen''s method.
In proving relation of trigonometric ratios we became confused that what should we do next, so to complete any question quickly what should we do?
Limit sin(1/x) when x tends to 0 is not definedCan be proved simply by multiplying and dividing by x then xsin(1/x)/x becomes 1/x as xsin(1/x)or for that matter sin(1/x)/1/x = 1 and limit reduces to 1/x which doesnt exist Also the proof can be that when x approcashes 0 from positive side 1/x tends to positive infinty and limit (right0 becomes sin(infinity) but when from left side 1/x tends to negative infinty so limit becomes -sin(infinit) which both can never b equal. so limit doesnt exist
Limit sin(1/x) when x tends to 0 is not definedCan be proved simply by multiplying and dividing by x then xsin(1/x)/x becomes 1/x as xsin(1/x)or for that matter sin(1/x)/1/x = 1 and limit reduces to 1/x which doesnt exist Also the proof can be that when x approcashes 0 from positive side 1/x tends to positive infinty and limit (right0 becomes sin(infinity) but when from left side 1/x tends to negative infinty so limit becomes -sin(infinit) which both can never b equal.
so limit doesnt exist
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