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As x tends to zero the value of 1/x tends to either ∞ or -∞. In this situation we will not be sure about the exact value of 1/x. As a result we will not be sure about the exact/approaching value of sin(1/x). We cant say anything about the value of sine function unless we know the angle and in this question we are not sure about the angle as at infinity it can take any value. We will be sure that the value of sin(1/x) will lie in [-1, 1] but not sure about a unique value. As in limits, it exists only when we get a unique value. Therefore we will say that the limit does not exist.
2 times n times n divided by n
The area of the base of a prism can be expressed as x2 + 4x + 1 and the height of the prism can be expressed as x - 3. What is the volume of this prism in terms of x? Because t
Which number below is described by the following statements? The hundredths digit is 4 and the tenths digit is twice the thousandths digit. a. 0.643 b. 0.0844 c. 0.446 d. 0.0142
introduction
Determine the inverse transform of each of the subsequent. (a) F(s) = (6/s) - (1/(s - 8)) + (4 /(s -3)) (b) H(s) = (19/(s+2)) - (1/(3s - 5)) + (7/s 2 ) (c) F(s) =
Town x and town y were 270km apart. a car started from town x towards town y at a uniform speed of 60km/hr, while a motorcycle started from town y to town x at a uniform speed of 9
Mike sells on the average 15 newspapers per week (Monday – Friday). Find the probability that 2.1 In a given week he will sell all the newspapers [7] 2.2 In a given day he will sel
need help with future value project
is 1 a prime number?
three towns are situated in such away that town B is 120 kilometers on a bearing of 030 degrees from town A. Town C is 210 kilometers on a bearing of 110 degrees from town A (a)ca
Limit sin(1/x) when x tends to 0 is not definedCan be proved simply by multiplying and dividing by x then xsin(1/x)/x becomes 1/x as xsin(1/x)or for that matter sin(1/x)/1/x = 1 and limit reduces to 1/x which doesnt exist Also the proof can be that when x approcashes 0 from positive side 1/x tends to positive infinty and limit (right0 becomes sin(infinity) but when from left side 1/x tends to negative infinty so limit becomes -sin(infinit) which both can never b equal. so limit doesnt exist
Limit sin(1/x) when x tends to 0 is not definedCan be proved simply by multiplying and dividing by x then xsin(1/x)/x becomes 1/x as xsin(1/x)or for that matter sin(1/x)/1/x = 1 and limit reduces to 1/x which doesnt exist Also the proof can be that when x approcashes 0 from positive side 1/x tends to positive infinty and limit (right0 becomes sin(infinity) but when from left side 1/x tends to negative infinty so limit becomes -sin(infinit) which both can never b equal.
so limit doesnt exist
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