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A: A using declaration makes it possible to employ a name from a namespace without the scope operator.
Project Description: Need to develop an expert advisor base on sthocastic oscilator with my own setting.. Very basic touch line OB/OS only but on my setting n condition Skill
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Purchasing Code Signing Certificate I want to purchase a Code Signing Certificate in good standing from someone in order to sign my .EXE programs with. Please be aware I do n
The default Constructor and Destructor If you fail to write a constructor and destructor function, the compiler automatically supplies them for you. These functions have publi
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You are given a collection of words, say as in a dictionary. You can represent it in the following compressed form: the first word will be followed by a sequence of a pair of numbe
A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concate
A: no, can't. The names of, precedence of, associativity of, and arity of operators is fixed through the language. In C++, there is no operator** so you cannot create one for a
Various ways of initializing the Arrays. - The for loop initializes 10 elements with the value of their index. void main() { const in
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