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Q. What is task identifier?
Each and every PVM task is uniquely recognized by an integer known as task identifier (TID) assigned by local pvmd. Messages are received from and sent to tids. PVM includes various routines which return TID values so that user application can recognize other tasks in system. PVM supports grouping of tasks too. A task may belong to more than one group as well as one task from one group can communicate with the task in other groups. To use any of group functions a program should be linked with libgpvm3.a.
Clustering has been existing since the 1980s when it was used in DEC's VMS systems. IBM's SYSLEX is a cluster approach for a mainframe system. Sun Microsystems, Microsoft, and othe
What is cyclomatic complexity? Cyclomatic complexity is a computer science metric (measurement) developed by Thomas McCabe used to generally calculate the complexity of a progr
Design a mod-12 Synchronous up counter. Ans. Design of a mod 12 synchronous counter by using D-flipflops. I state table Present state Next
Q. Combined Parallel Work-sharing Constructs? Combined parallel work sharing constructs are shortcuts for specifying a work sharing construct nested instantaneously in a parall
en a five station token bus LAN with station addresses of 3000, 500, 100, 70, and 50. Stations with addresses of 5000, 4000, 400, 90, and 60 are waiting to enter the ring. Assume a
SSTF stands for ? Ans. Shortest-Seek-time-first scheduling.
What can you say about the existence of a stationary point in the interval [ 1; 3] for the function f (x) = x 2 2x 3.
What is .NET / .NET Framework? It is a Framework in which Windows applications might be developed and run. The Microsoft .NET Framework is a platform for building, deploying,
Explain with the help of Nyquist theorem, the data rate limitations in PSTN's. Data rates in PSTNs : A voice channel in a public switched telephone network is band restricted
The Karnaugh map for a SOP function is given below in figure. Determine the simplified SOP Boolean expression. Ans. F= B'C' + A'C'D + B'D'
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