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What is Random access memory (RAM)
This is a volatile memory (i.e. contents are lost when computer is switched off). A user can write or delete data and read the contents. Before a program can be ran it should first be loaded into RAM that allows CPU to access the program. Battery-backed RAMs overcome data loss on switching power off though are outside the scope of these booklets.
(NOTE: For completeness, it's worth mentioning that two types of RAM exist termed as SRAM (static RAM) and DRAM (dynamic RAM) - SRAM doesn't need to be constantly refreshed to retain its memory unlike DRAM. Also consider that computers use cache which is a part of memory made from SRAM. Memory caching works as programs generally access the same data or instructions over and over again. By retaining as much information as possible in SRAM, computer operates more quickly (cache is generally termed level 1, 2 or 3 (termed L1, L2 or L3)).
advantages of dda line algoritm
Simplify the Boolean expression F = C(B + C)(A + B + C). Ans. Simplification of the given Boolean Expression F = C (B +C) (A+B+C) given as F = C (B+C) (A+B+C) = CB + CC [(A+B+C
You have been contacted by Jean-Luc Picard commanding officer of Star Trek: The Next Generation. The Commander needs your support to develop a software routine to simulate the Robo
i need help
Take the following recurrence relation consider only for n = 2k for integers k ≥ 1: T(2) = 9, and for n ≥ 4, T(n) = n + T(n /2). Three students were working together in a stu
What is meant by scan code? When a key is pressed on the keyboard, the keyboard controller places a code take to the key pressed into a part of the memory known as the keyboar
What is computer science
What are the features of Client/Server Computing? Although there are several different configurations, different hardware and software platforms and even dissimilar network pro
One Erlang is equal to (A) 3600 CCS (B) 36 CCS (C) 60 CCS (D) 24 CCS Ans: One Erlang is equivalent to 3600 CCS.
(a) Convert the following number to single precision IEEE 754 based on the procedure described in class and in the notes. Express the result in hexadecimal. Show all your work.
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