Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
The order of a reaction is occasionally changed by conditions. Consider a chemical reaction between two substances where one reactant is there in large excess. During the hydrolysis of 0.01 mol of ethyl acetate with 10 ml of water, amounts of the various constituents at the beginning (t = 0) and complexion (t) of the reaction are given as under The concentration of water does not get altered much during the course of the reaction. So, in the rate equation Rate = k’ [CH3COOC2H5] [H2O] The term [H2O] can be taken as constant. The equation, thus, becomes Rate = k [CH3COOC2H5] Where k = k’ [H2O] And the reaction behaves as first order reaction. Such reactions are called pseudo first order reaction. Conversion of cane sugar is one more pseudo first order reaction. Rate = k [C12H22O11]
The following cell is used for measuring the partial pressure of oxygen at 700 o C. (Pt) Cu 2 Cu 2 0 / 0.85 ZrO 2 - 0.l5 CaO / O 2 (Pt) Knowing that conduction through the
Short note on synthetic rubber. S ol. Synthetic rubber: main types of synthetic rubbers: 1. Styrene rubber: Buna-S; Bu-Butadiene; Na=sodium; = Styrene
Q: For a homogeneous reaction in which the reactants and products are solutes in a solution, write a rigorous relation between the standard molar reaction enthalpy and the temperat
why element belonging to group 3 to 12 are trnsicition element
i need help reading this IR chart to figure out what the compound is
The amount of electricity required to produce one mole of copper from sulphate solution will be how many faradays? Ans) 2 faraday of electricity is required to produce one mol
I UNDERSTAND THE CONCEPT. I AM CONFUSED ABOUT A SPECIFIC EQUATION OR FORMULA TO SHOW HOW THE BONDS ARE BROKEN THROUGH HYDROLYSIS.
1 gm of a metallic oxide on reduction gives 0.68 gm of the metal. ans) Mass of metal/mass of oxygen=eq. mass of metal/eq. mass of oxygen. applying this we get .68/.32=x/8 x=1
equivalent weight of h3po2
anomalous behaviour of beryllium
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd