User Account

All Pages

What is Oscillating Sort?, Data Structure & Algorithms

Assignment Help:
For the Oscillating sort to be applied, it is necessary for the tapes to be readable in both directions and able to be quickly reversed. The oscillating sort is superior to the polyphase for more than 6 tape units. The oscillating sort derives its name from the fact that the sort is performed by oscillating between distributions and merging. Rather than distribute all the inputs to the tapes and then commence merging, some of the inputs are distributed, then merged, and then more are distributed. The sort works exactly if the number of initial runs is a power of T - 1 where T is the number of working tapes used in the sort. When the number of initial runs is not a power of T -1 it is assumed that dummy runs are present to make up the difference.

Principle: Distribute all the inputs to the tapes and then commence merging. Some of the inputs are distributed, and then merged, and then more are distributed. This process is repeated till a sorted list is obtained.

Algorithm:

1. Let A be the given list of N unsorted elements.

2. Let T be the number of working tapes and R be the number of runs.

3. Initialize an index variable I ß 2.

4. Distribute T - 1 runs one in each working tape leaving T[I] empty.

5. Merge the above runs and put the new run in T[I].

6. Increment the value of I.

7. Repeat steps 4 to 6 till all inputs are exhausted.

8. The runs of equal length are merged and placed in empty tape.

In this example, five tapes are used with four of them considered as the working tapes. The first one simply holds the input. Step 2 shows the first distribution phase in which records with values 14, 26, and 3 are distributed on tapes 3, 4 and 5 respectively. In step 3 these are merged backward and the run (3 14 26) is placed on tape 2. Once more distribution is done in step 4 leaving 15 on tape 2, 6 on tape 4, and 35 on tape 5. These are merged again and placed on tape 3. Step 6 is the final distribution phase placing 19, 28 and 22 on tapes 2, 3 and 5 respectively. In step 7 these are merged and placed on tape 4. At this point the inputs are exhausted and have three runs of equal length. These three runs are merged and placed on tape 5.

Related Discussions:- What is Oscillating Sort?

Binary tree and binarytree parts, Q. What do you understand by the term Bin...

Q. What do you understand by the term Binary Tree? What is the maximum number of nodes which are possible in a Binary Tree of depth d. Explain the terms given below with respect to

Stickly binary tree, stickly binary tree

stickly binary tree

Whether the infix expression has balanced parenthesis or not, Using stacks,...

Using stacks, write an algorithm to determine whether the infix expression has balanced parenthesis or not Algorithm parseparens This algorithm reads a source program and

Division-remainder hashing, According to this, key value is divided by any ...

According to this, key value is divided by any fitting number, generally a prime number, and the division of remainder is utilized as the address for the record. The choice of s

Tape sort based on fibonacci distribution, how does we get fibonacci table ...

how does we get fibonacci table in tape sort

List various problem solving techniques, List various problem solving techn...

List various problem solving techniques. There are two techniques:- 1.  Top down 2.  Bottom- up

Algorithm to evaluate expression given in postfix notation , Q. Write down ...

Q. Write down an algorithm to evaluate an expression given to you in postfix notation. Show the execution of your algorithm for the following given expression. AB^CD-EF/GH+/+*

Values are automatically assigned to those array elements, What values a...

What values are automatically assigned to those array elements which are not explicitly initialized? Garbage values are automatically assigned to those array elements that

What is the best case complexity of quick sort, What is the best case compl...

What is the best case complexity of quick sort In the best case complexity, the pivot is in the middle.

Add the special form let to the metacircular interpreter, (1)  (i) Add the ...

(1)  (i) Add the special form let to the metacircular interpreter Hint: remember let is just syntactic sugar for a lambda expression and so a rewrite to the lambda form is all t

Write Your Message!

Captcha
Order Assignment

Featured Services

Order Now

Popular Subjects

Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

Submit Assignment

Academics

Major Subjects

Majors

Get In Touch

whatsapp: +91-977-207-8620

Phone: +91-977-207-8620

Email: [email protected]

TERMS & POLICIES

HELP & SUPPORT

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd