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Q. What is CODE SEGMENT?
The logical program segment is termed as code segment. When linker links a program it makes a note in header section of program's executable file defining the location of code segment when DOS invokes the loader to load an executable file in memory then loader reads that note. As it loads the program in memory loader also makes notes to itself of exactly where in memory it essentially places every one of the program's other logical segments. As loader hands execution over to program it has just loaded it sets CS register to address the base of segment identified by linker as code segment. This reduces each instruction in code segment addressable in segment relative terms in form CS: xxxx.
Linker also presumes by default that first instruction in code segment is aimed to be first instruction to be executed. That instruction shall appear in memory at an offset of 0000H from base of code segment so linker passes that value on to loader by leaving an another note in header of program's executable file. Loader sets IP (Instruction Pointer) register to that value. This sets CS:IP to segment relative address of first instruction in program.
Q. Task Information Displays in Search-based tools? Task Information Displays principally give visualization of different locations in parallel program where bottlenecks have o
Q. What is CODE SEGMENT? The logical program segment is termed as code segment. When linker links a program it makes a note in header section of program's executable file defin
Flynn's Classification This classification was early proposed and studied by Michael Flynn in 1972. Flynn did not believe the machine architecture for organization of parallel
l need a help for my project pllz:) Write a program that will simulate ATM machine. The Program should prompt the user to enter a valid PIN password number of 5 digits (PIN: 12312)
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Define end series and its application
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Q. Example on Multi-statement FORALL construct? The subsequent statements set every element of matrix X to sum of its indices. FORALL (i=1:m, j=1:n) X(i,j) = i+j an
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