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Q. What is Capacitor-Based Keyboards?
These keyboards are based on the idea of Capacitance. A simple capacitor comprises a pair of conductive plates having opposite charges and separated by an insulator. This arrangement produces a field between plates proportional to closeness of plates. Changing the distance between plates roots current to flow. Capacitive keyboards have etched circuit boards with tin and nickel-plated copper pads performing as capacitors under every key (a key is technically known as a station). Every key press presses a small metal-plastic circle down causing electric flow. These keyboards work well however have the drawback that they follow an indirect scheme though they have a longer life than contact-based keyboards. These keyboards were initiated by IBM.
Q. Illustration of an instruction cycle? Instruction cycle displayed in given figure comprises subsequent stages: First address of the subsequent instruction is calculat
The Karnaugh map for a SOP function is given below in figure. Determine the simplified SOP Boolean expression. Ans. F= B'C' + A'C'D + B'D'
Explain the multiple bus organization structure with neat diagram. The multiple bus organization is using more buses instead of one bus to decrease the number of steps needed an
Q. Explain about Registers? A register is a group of flip-flops that store binary information and gates that controls when and how information is transferred to register. An n-
Basic Operational Concepts of a Computer: Most of computer operations are executed in the ALU (arithmetic and logic unit) of a processor. For an example: to add 2 numb
Why some languages are not decidable or even Turing - recognizable? The reason that there are uncountable many languages yet only countably many Turing machines.
Explain the meaning of LISTEN socket primitive The listen Primitive: After identifying a protocol port a server should instruct the operating system to place a socket
Which digital logic family has minimum power dissipation ? Ans. The minimum power dissipation of digital logic family is CMOS. CMOS being an unipolar logic family, occupy a to
How can we change almost any algorithm to have a good best case running time? Check whether the input constitutes an input at the very starting Or else run the original algo
I n a time division space switch the size of the control memory is N and its Width: (A) Log 10 M (B) Log e M (C) Log N M (D) Log 2 M Where N are the ou
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