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Presume you are asked to find the characteristics of the image of an actual physical object formed by a single lens and you obtain a negative value for the magnification. What does this notify you about the image?
Answer:
This is merely a human-established convention. A negative value for the exaggeration means that the image is upside down (inverted).
a wave of eqn y=0.005sin(8x-3t).find displacement when x=0.3 t=20s?in the answer given y=0.005sin(80*3-0.3*20)= y=0.005sin(-36+12pi).what is this 12pi?
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In a Newton's ring experiment the diameter of n th ring is 0.46 cm it got shrink to a diameter of 0.40 cm when a liquid is given between the plane glass plate and Plano convex len
#question.knk
why does our image in the mirror not appear upside down
Explain about the Homojunction Laser in brief. Homojunction Laser: Assume that GaAs be doped with T providing n-type material and with Ge providing p-type material. In forwa
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