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What do you mean by hash clash?
Hashing is not perfect. Occasionally, a collision occurs when two different keys hash into the same hash value and are assigned to the same array element. Programmers have come up with various techniques for dealing with this conflict. A common way to deal with a collision is to make a linked list of entries that have the similar hash value. For example, let the key of every entry hashes to the similar hash value and this result in both being assigned to the similar array element of the hashtable.
Write an algorithm to count number of nodes in the circular linked list. Ans. Counting No of Nodes in Circular List Let list be a circular h
Area Subdivision Method In this method, the viewport is examined for clear decisions on the polygons situated in it, in regard to their overlap and visibility to the viewer. Fo
In what ways we can get the context sensitive F1 help on a field?' Data element documentation. Data element additional text in screen painter. Using the process on help r
Document processing is quickly becoming one of the dominant functions of computers. Computers are utilized to edit, search & transport documents over the Internet, and to display d
State about the Simple types - Built-In Types Values of the carrier set are atomic, that is, they can't be divided into parts. Common illustrations of simple types are inte
This unit dealt along with the methods of physically storing data in the files. The terms fields, records & files were described. The organization types were introduced. The sev
Explain the representations of graph. The different ways of representing a graph is: Adjacency list representation : This representation of graph having of an array Adj of
Determine the class invariants- Ruby Ruby has many predefined exceptions classes (like ArgumentError) and new ones can be created easily by sub-classing StandardError, so it's
what is folding method?
Evaluate the frequency counts for all statements in the following given program segment. for (i=1; i ≤ n; i ++) for (j = 1; j ≤ i; j++) for (k =1; k ≤ j; k++) y ++;
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