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If the areas of two sections of a garden are 6a + 2 and 5a, what is the difference among the areas of the two sections within terms of a?
Because the question asks for the difference among the areas, you required to subtract the expressions: 6a + 2 - 5a. Subtract such as terms: 6a - 5a + 2 = 1a + 2; 1a = a, so the implied answer is a + 2.
1. Solve the right triangle. B = 135 c = 3.72 A ≈ ____° (round to the nearest tenth as needed) 2. Solve the right triangle, where a =4 and b =10 The length of
G raph y = sec ( x ) Solution: As with tangent we will have to avoid x's for which cosine is zero (recall that sec x =1/ cos x) Secant will not present at
Hi may i know how to substract the (ID)colum matrix from (K)square matrix as per equation below. E = (K - ID)^-1 S K is m*m matrix I is idntity matrix d is column vector s is col
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Method of disks or the method of rings One of the simple methods for getting the cross-sectional area is to cut the object perpendicular to the axis of rotation. Carrying out
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a person having rs.10 shares of value rs.6000 in a company which pays a 7% dividend invested the money gained by selling those shares and bought rs.25 shares at rs.24 per share in
to use newspaper and report on share and dividend
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