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Harold is tiling a rectangular kitchen floor with an area that is expressed as x2 + 6x + 5. What could the dimensions of the floor be in terms of x?
Because area of a rectangle is length × width, seems for the factors of the trinomial to ?nd out the two dimensions. First check to see if there is a general factor in each of the terms or if it is the difference between two perfect squares, and it is neither of these. The next step would be to factor the trinomial within two binomials. To do this, you will be doing a method that resembles FOIL backwards. (First terms of each binomial multiplied, Outer terms in each multiplied, Inner terms of each multiplied, and Last term of every binomial multiplied.) First results in x2, so the ?rst terms must be (x )(x ); Outer added to the Inner combines to 6x, and the Last is 5, so you required to ?nd out two numbers in which add to generate +6 and multiply to generate +5. These two numbers are +1 and +5; (x + 1)(x + 5).
Grouped Data For grouped data of a paired population where, f is the
Find out the surface area of the solid acquired by rotating the following parametric curve about the x-axis. x = cos 3 θ y = sin 3 θ 0 ≤ θ ≤ ?/2 Solution We wil
if P is a point in the interior of a triangles ABC,prove that AB>BC+CA
An apartment complex contains 250 apartments to rent. If they rent x apartments then their monthly profit is specified by, in dollars,, P ( x
how do they solve log9 = ... 27
what is infinite? ..
Ut=Uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0 u(1,t)=-A/b^2 exp(-b)
Eliminate the parameter from the subsequent set of parametric equations. X = t 2 + t Y = 2t - 1 Solution: One of the very easy ways to eliminate the parameter is to
Here are four problems. Four children solved one problem each, as given below. Identify the strategies the children have used while solving them. a) 8 + 6 = 8 + 2 + 4 = 14 b)
How to Dealing With Exponents on Negative Bases ? Exponents work just the same way on negative bases as they do on positive ones: (-2)0 = 1 Any number (except 0) raised to the
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