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What are the Application-oriented languages
Application-oriented languages are highest level, meaning very easy to write and assembly languages are the lowest, meaning hardest to write. Even though it is easier to develop application oriented language programs, their corresponding machine code may not be efficient as preprocessors and compilers may not be sophisticated enough to generate an efficient machine code. Conversely, developing a large assembly language program may not be practical because of the complexity of the language.
Highly Encoded micro-instructions Encoded bits required in micro-instructions are small. It provided an aggregated view that is a higher view of CPU as just an encoded
The number 140 in octal is equivalent to decimal number ? Ans. (140) 8 = (96) 10 As 1 x 8 2 + 4 x 8 + 0x 1 = 64 + 32 = 96
What is secondary list? It permits you to enhance the information presented in the basic list. The user can, for example, select a line of the basic list for which he require
shell script to find the factorial of a given number using the for loop
Q. What is disk access time? The disk access time has two key components: Seek Time: Seek time is the time for disk arm to move heads to the cylinder comprising the desi
create a stored procedure to debit a bank account user must enter account no. and amount to debited from account .the minimum balance in account should be 500. if the debited amoun
Define asynchronous bus. Asynchronous buses are the ones in which every item being transferred is accompanied by a control signal that shows its presence to the destination uni
What are the Barcode readers These collect data from printed barcodes and allow automatic stock control in, for illustration, supermarkets.
Convert binary number in two's compliment form 0100 1000. Converting the binary number into 2's compliment from 0100 1000 is given below: 01001000 => 10111000
Explain the Race Around Condition? Consider the inputs of the JK flipflop j=1 and k=1 and Q=0 when a clock pulse of width tp is applied the output will change from 0 to 1 after
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