Voltage doubler, Electrical Engineering

Assignment Help:

Voltage Doubler:

The network of Fig. is a half wave voltage doublers. During the positive voltage half cycle across the transformer, secondary diode D1 conducts, charging capacitor C1 up to the peak rectified voltage charges capacitor C1 to Vm with the polarity shown in fig. during the negative half cycle of the secondary voltage, diode D1 is cut off and diode D2 conducts charging capacitor C2. Since diode D2 acts as a short during the negative half cycle, we can sum the voltages a round outside loop. On the next positive half cycle, diode D2 is no conducting and capacitor C2 will discharge through the load. If no load is connected across capacitor C2, both capacitors stay charged C1 to VM and C2 to 2Vm. If, as would be expected, there is a load connected to the output of the voltage doublers, the voltage across capacitor Cdrops during the positive half cycle and the capacitor is recharged up to 2VM during the negative half cycle. The output waveform across capacitor Cis that of half wave signal filtered by a capacitor filter. The peak inverse voltage across each diode is 2VM. Another doublers circuit is the full wave doublers as shown in fig. during the positive half cycle of transformer secondary voltage diode d1 conducts charging capacitor C1 to a peak voltage Vm. Diode D2 is nonconduction at this time. During the negative half cycle, diode D2 conducts charging capacitor C2 while diode D1 is nonconducting. If no load current is drawn from the circuit, the voltage across capacitors Cand C2 is 2Vm. If load current is drawn from the circuit, the voltage across capacitors C1 and C2 is the same as that across a capacitor fed by a full wave rectifier circuit. One difference is that the effective capacitance is that of C1 and C2 in series, which is less than the capacitance of either Cor C2 alone. The lower capacitor value will provide poorer filtering action than the single capacitor filter circuit. The peak inverse voltage across each diode is 2Vm as it is for the filter capacitor circuit. During the negative half cycle, diode D2 conducts charging capacitor C2 while diode D1 is nonconducting. If no load current is drawn from the circuit, the voltage across capacitors C1 and Cis 2Vm. If load current is drawn from the circuit, the voltage across capacitor C1 and C2 is the same as that across a capacitor fed by a full wave rectifier circuit. One difference is that the effective capacitance is that of C1 or C2 alone. The lower capacitor value will provide poorer filtering action than the single capacitor filter circuit. The peak inverse voltage across each diode is 2Vm as it is for the filter capacitor circuit. In summary, the half wave or full wave voltage doublers circuits provide twice the peak voltage of the transformer secondary while requiring no center tapped transformer and only 2VmPIV rating for the diodes.


Related Discussions:- Voltage doubler

Explain thermosetting plastic materials, Explain Thermosetting Plastic Ma...

Explain Thermosetting Plastic Materials. Thermosetting Plastic Materials: They undergo huge changes while subjected to high temperatures for rather sometimes. They are call

Assignment, Hi, I got assignment to design a power electronic system Design...

Hi, I got assignment to design a power electronic system Design the circuit and select the appropriate components for that circuit to fulfil the requirements of the device. Regards

Compute the minimum line current for the motor, A three-phase, wye-connecte...

A three-phase, wye-connected, four-pole, 400- V, 60-Hz, 15-hp synchronous motor has a synchronous reactance of 3  per phase and negligible armature resistance. The data for its no

Calculate the bandwidth and input-output resistance, Using the LM741operati...

Using the LM741operational amplifier build a voltage amplifier with the voltage gain of  |A V | = 500 v/v ± = 20%. Measure all necessary parameters of the amplifier (as per deliver

Determine rc and resistance, Q. A silicon npn BJT is biased by the method s...

Q. A silicon npn BJT is biased by the method shown in Figure, with R E = 240 , R 2 = 3000 , and V CC = 24 V. The operating point corresponds to V BEQ = 0.8V, I BQ = 110 µA,

Jfet common drain amplifier, Q. JFET Common Drain Amplifier? The common...

Q. JFET Common Drain Amplifier? The common drain FET amplifier is similar to the common collector configuration of the bipolar transistor. A general common drain JFET amplifier

Classify the conducting materials, Classify the conducting materials. ...

Classify the conducting materials. Conducting materials are classified by low resistivity materials and high resistivity materials. Low resistivity materials: The conduct

What is ringtopology, Q. What is RingTopology? In ring topology, all us...

Q. What is RingTopology? In ring topology, all user nodes are connected with physical path acting as links of a chain and last user node is connected back to the first node. A

Advantages and disadvantages of alloying steel with silicon, State the adva...

State the advantages and disadvantages of alloying steel with silicon for use as magnetic materials in transformer and electric machines. Extensive utilize, is made of iron-sil

How do you find the insulation resistance of transformer, Q. How do you cal...

Q. How do you calculate the insulation resistance of transformer and what is the minimum value? Ans. The insulation resistance of the transformer will be calculated by using

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd