Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Voltage Doubler:
The network of Fig. is a half wave voltage doublers. During the positive voltage half cycle across the transformer, secondary diode D1 conducts, charging capacitor C1 up to the peak rectified voltage charges capacitor C1 to Vm with the polarity shown in fig. during the negative half cycle of the secondary voltage, diode D1 is cut off and diode D2 conducts charging capacitor C2. Since diode D2 acts as a short during the negative half cycle, we can sum the voltages a round outside loop. On the next positive half cycle, diode D2 is no conducting and capacitor C2 will discharge through the load. If no load is connected across capacitor C2, both capacitors stay charged C1 to VM and C2 to 2Vm. If, as would be expected, there is a load connected to the output of the voltage doublers, the voltage across capacitor C2 drops during the positive half cycle and the capacitor is recharged up to 2VM during the negative half cycle. The output waveform across capacitor C2 is that of half wave signal filtered by a capacitor filter. The peak inverse voltage across each diode is 2VM. Another doublers circuit is the full wave doublers as shown in fig. during the positive half cycle of transformer secondary voltage diode d1 conducts charging capacitor C1 to a peak voltage Vm. Diode D2 is nonconduction at this time. During the negative half cycle, diode D2 conducts charging capacitor C2 while diode D1 is nonconducting. If no load current is drawn from the circuit, the voltage across capacitors C1 and C2 is 2Vm. If load current is drawn from the circuit, the voltage across capacitors C1 and C2 is the same as that across a capacitor fed by a full wave rectifier circuit. One difference is that the effective capacitance is that of C1 and C2 in series, which is less than the capacitance of either C1 or C2 alone. The lower capacitor value will provide poorer filtering action than the single capacitor filter circuit. The peak inverse voltage across each diode is 2Vm as it is for the filter capacitor circuit. During the negative half cycle, diode D2 conducts charging capacitor C2 while diode D1 is nonconducting. If no load current is drawn from the circuit, the voltage across capacitors C1 and C2 is 2Vm. If load current is drawn from the circuit, the voltage across capacitor C1 and C2 is the same as that across a capacitor fed by a full wave rectifier circuit. One difference is that the effective capacitance is that of C1 or C2 alone. The lower capacitor value will provide poorer filtering action than the single capacitor filter circuit. The peak inverse voltage across each diode is 2Vm as it is for the filter capacitor circuit. In summary, the half wave or full wave voltage doublers circuits provide twice the peak voltage of the transformer secondary while requiring no center tapped transformer and only 2VmPIV rating for the diodes.
a. Write the advantages of choosing a single purpose processor over a general purpose processor. b. List out the hardware units that must be there in the embedded systems. c.
A quantizer has 130 quantum levels that exactly span the extremes of a symmetrically ?uctuating message with step size δv = 0.04 V. Determine the following: (a) |f(t)|max.
Derive the mathematical 3-D heat conduction equation in Spherical Coordinates? A furnace is made up of three layers of thicknesses 250 mm, 150 mm nad 100 mm with thermal conduct
Explain in detail the operation of 8255 in mode1 taking suitable example. In mode1, Ports A and B are programmed as input or output ports and Port C is used for handshaking.
Find I and V in the figure using ideal diode model
what is a armature reaction ?? give some concepts on double rotating field theory?? thanks
why do we prefer h model ampliflying circuits?
Define Serial In - Serial Out Shift Registers? An essential four-bit shift register can be constructed using four D flip-flops. The register is the first cleared forcing all fo
hi can you help with newton raphson?
Q. Grade of Service In loss systems? Grade of Service : In loss systems, traffic carried by the network is normally lower than actual traffic offered to the network by subscri
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd