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This method is more systematic and orderly than least cost method. Here penalties for each column and row of the transportation table are determined, and the row or column with largest penalty is chosen for allocation. Then the cell with lowest cost form the selected row column is allocated the maximum possible.
After this the row or column whose supply or demand is exhausted is exhausted is deleted and the penalties are again calculated for the shrunken table. The procedure continue still full demand supply is exhausted. Here penalty of each row column = ( second lowest - lowest costs of that row / column.
Maximize6x1+8x2+5x3,st,labour3x1+4x2+5x3 =0 then brefly explain x1,x2,x3;term labour,metal&plastic;the160hours;x1,x2&x3>=0
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Maximize Z= 3x1 + 2X2 Subject to the constraints: X1+ X2 = 4 X1 - X2 = 2 X1, X2 = 0
Ask question #Minimum 100 words what can engineer planner do in métallurgie accepted#
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a paper mill prodecs two grades of paper viz., X and Y. Because of raw material restrictions, it cannot produce more than 400 tons of grade X paper and 300 tons of grade Y paper in
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