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The string of a pendulum is horizontal. Mass of the bob is m. Now the string is released, what is the tension in the string at lowest position Ans) If string length is L, Conserving energy, velocity at lowest point is (2gL)1/2 Centripetal force mv2/L= 2mg. T- mg= mv2/LT= 3mg
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derive an expression for drift velocity
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HOW TO DRAW OR GET B-H CURVES & THEIR HYSTERISIS LOOPS FOR NON MAGNETIC MATREIALS
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