Velocity and acceleration - three dimensional space, Mathematics

Assignment Help:

Velocity and Acceleration - Three Dimensional Space

In this part we need to take a look at the velocity and acceleration of a moving object.   

From Calculus I we are familiar with that given the position function of an object that the velocity of the object is the 1st derivative of the position function and the acceleration of the object is the 2nd derivative of the position function. 

Thus, given this it shouldn't be too surprising that whether the position function of an object is specified by the vector function  r→(t) then the velocity and acceleration of the object is illustrated by,

v (t) = r'(t)

a (t) = r'' (t)

Note: The velocity and acceleration are as well going to be vectors also.

In the study of the motion of objects the acceleration is frequently broken up into a tangential component, aT, and the normal component denoted as aN.  The tangential component is the part or element of the acceleration which is tangential to the curve and the normal component is the part of the acceleration which is normal or orthogonal to the curve.  If we do this we can write down the acceleration as,

a = aT T+ aNN

where T and N stands for the unit tangent and unit normal for the position function.

If we illustrate v = ||v (t)|| then the tangential and normal components of the acceleration are specified by,  

aT = v' =r' (t).r''(t) /(||r' (t)||)

aN = kv2 = ||?r' (t) *r" (t)|| / ||r' (t)||

in which k is the curvature for the position function.

There are two (2) formulas to employ here for each component of the acceleration and when the second formula may seem excessively complicated it is frequently the easier of the two.  In the tangential component, v, might be messy and calculating the derivative may be unpleasant.  In the normal component we will previously be computing both of these quantities in order to get the curvature and thus the second formula in this case is certainly the easier of the two.


Related Discussions:- Velocity and acceleration - three dimensional space

Factoring out a common monomial factor, Factoring Out a Common Monomial Fac...

Factoring Out a Common Monomial Factor? Say you have a polynomial, like 3x 4 y - 9x 3 y + 12x 2 y2 z and you want to factor it. Your first step is always to look for t

MATLAB, Program of "surface of revolution" in MATLAB

Program of "surface of revolution" in MATLAB

Find the value of x of eagle , A fox and an eagle lived at the top of a cli...

A fox and an eagle lived at the top of a cliff of height 6m, whose base was at a distance of 10m from a point A on the ground. The fox descends the cliff and went straight to the p

Solve the value of x and y , 7(y + 3) - 2(x + 2) = 14, 4 (y - 2) + 3(x ...

7(y + 3) - 2(x + 2) = 14, 4 (y - 2) + 3(x - 3) = 2 Ans:    7(y + 3) - 2 (x+ 2) = 14          --------- (1) 4(y- 2) + 3(x - 3) = 2 ----------(2) From (1) 7y +21 -

Find out the surface area of the solid, Find out the surface area of the so...

Find out the surface area of the solid acquired by rotating y = √ (9-x 2 ), - 2 x 2 about the x-axis. Solution The formula that we'll be using here is, S = ∫ 2Πyds

Marketing management , Draw the typical profile(s) of Shoppers'' Stop custo...

Draw the typical profile(s) of Shoppers'' Stop customers segments.

Abels theorem, If y 1 (t) and y 2 (t) are two solutions to y′′ + p (t ) ...

If y 1 (t) and y 2 (t) are two solutions to y′′ + p (t ) y′ + q (t ) y = 0 So the Wronskian of the two solutions is, W(y 1 ,y 2 )(t) = =

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd