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Gopher Gallery consists of a shopping mall and a cart ride that covers the 150 acre habitat. There are m visitors and n single-person vehicles. Visitors stroll around the mall at their leisure, then line up for the cart ride. When a cart is available, it allows the single passenger to climb aboard and drives around the habitat for a random amount of time. If the n carts are all taken, then a future rider waits; if a vehicle is available but no one is waiting, then the vehicle waits. The solution to this problem must synchronize visitor tasks and vehicle tasks using semaphores. Below is a potential solution. Correct any issues with this code, if any exist. Explain your position in detail. Semaphore vehicleAvailable = 0, vehicleTaken = 0, vehicleFilled = 0, visitorReleased = 0; Visitor() { vehicleAvailable.wait(); vehicleTaken.signal(); vehicleFilled.wait(); visitorReleased.wait(); } Vehicle() { while(True) { vehicleAvailable.signal(); vehicleTaken.wait(); vehicleFilled.signal(); Drive through habitat for some arbitrary amount of time; visitorReleased.signal(); } }
Is it probable to have a deadlock involving only one single process? Describe your answer. Answer: No This pursue directly from the hold-and-wait condition.
Write about critical regions and monitors. Critical region definition Monitor definition Implementation of the conditional-region construct Syntax of monitor Monito
i need the job to be done within 3days
Q) a. Given that the first three necessary conditions for a deadlock are in place, comment on the feasibility of the following strategy. All processes are given unique priorities.
What are the benefits of multiprogramming? Responsiveness : Multithreading is an interactive application may permit a program to continue running even if part of it is block
shell script that accepts two directory names as arguments and delete those file in the second directory that are identical to the file in the first
#include #include #include #include #include int main(void) { int pchan[2], pid, rval, cvar; char buf[20]; if (pipe(pchan) == -1){
Determining the time quantum for a job is a critical task. Given the assumptions that the average switching time between processes is s, and the average amount of time an I/O bo
Synchronization serves two purposes: 1) to ensure safety for updates on shared data (e.g. to avoid races conditions), and 2) to coordinate and order actions taken by threads (e.g.
Define UnixWare UnixWare manages resources at the process level. Each resource allocated to the application is actually allocated to the process representing the application. C
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