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The angles between three non-zero and non coplanar vectors a,b and c are α between b and cand β between c and aand γ between a and b.The vector u and v are defined by u=(aXb)Xc;v=aX(bXc).If u is perpendicular to v, then show that eithera is perpendicular to cor cosβ=cosα.cosγ . solution) Given that u=(axb)xc, v=ax(bxc), both the vectors are equal in magnitude because of the associated law, and u.v=0, therefore it must be true that a.c=0, because excluding a and c , b is not situated at right angles so angle between a and c is 90.
Binomial Distribution Consider a batch of N light bulbs. Each bulb may be defective (S) or non-defective (F). The experiment involves selecting a light bulb and checking whethe
Factoring polynomials is probably the most important topic. We already learn factor of polynomial .If you can't factor the polynomial then you won't be able to even start the probl
Properties of Dot Product - proof Proof of: If v → • v → = 0 then v → = 0 → This is a pretty simple proof. Let us start with v → = (v1 , v2 ,.... , vn) a
write CxD being sure to use appropriate brackets and find n(CxD)
Find out if the following series is convergent or divergent. Solution There really is not very much to these problems another than calculating the limit and then usin
The following relation is not a function. {(6,10) ( -7, 3) (0, 4) (6, -4)} Solution Don't worry regarding where this relation came from. It is only on
Consider a class of 55 students. The student names are placed in a hat & 3 names are randomly drawn without replacement. a) If the first person drawn was named the class presi
Factor following. x 2 - 20 x + 100 Solution In this case we've got three terms & it's a quadratic polynomial. Notice down as well that the constant
Prove that if f and g are functions, then f intersect g is a function by showing f intersect g = glA A={x:g(x)=f(x)}
Derivative for the trig function: We'll begin with finding the derivative of the sine function. To do this we will have to utilize the definition of the derivative. It's been wher
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