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The angles between three non-zero and non coplanar vectors a,b and c are α between b and cand β between c and aand γ between a and b.The vector u and v are defined by u=(aXb)Xc;v=aX(bXc).If u is perpendicular to v, then show that eithera is perpendicular to cor cosβ=cosα.cosγ . solution) Given that u=(axb)xc, v=ax(bxc), both the vectors are equal in magnitude because of the associated law, and u.v=0, therefore it must be true that a.c=0, because excluding a and c , b is not situated at right angles so angle between a and c is 90.
In a right triangle ABC, right angled at C, P and Q are points of the sides CA and CB respectively, which divide these sides in the ratio 2: 1. Prove that 9AQ 2 = 9AC 2 +4BC 2
Evaluate subsequent proportion: Example 2: If 5 pounds of apples cost 80 cents, how much will 7 pounds cost? Solution: By using x for the cost of 7 pounds of appl
Solve the subsequent quadratic equation: Solve the subsequent quadratic equation through taking the square roots of both sides. 3x 2 = 100 - x 2 Solution: Step 1
(a) Using interpolation, give a polynomial f ∈ F 11 [x] of degree at most 3 satisfying f(0) = 2; f(2) = 3; f(3) = 1; f(7) = 6 (b) What are all the polynomials in F 11 [x] which
The Dow Jones Industrial Average fell 2% presently. The Dow began the day at 8,800. What was the Dow at the end of the day after the 2% drop? The Dow lost 2%, so it is worth 9
Example: Find out which of the following equations functions are & which are not functions. y= 5x + 1 Solution The "working" definition of fu
what is the quotient of 3 and n?
Describe Visualize Solutions of Simultaneous Equations ? By drawing the graph of each equation in a system of equations, you can see a picture of the system's solutions. Fo
Evaluate following integrals. (a) ∫ 3e x + 5 cos x -10 sec 2 x dx (b) ( 23/ (y 2 + 1) + 6 csc y cot y + 9/ y dy Solution (a) ∫ 3e x + 5 cos x -10 sec 2 x
Trig Substitutions - Integration techniques As we have completed in the last couple of sections, now let's start off with a couple of integrals that we should previously be
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