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Using %ROWTYPEThe %ROWTYPE attribute gives a record type which represents a row in a table (or view). The record can store the whole row of data selected from the table or fetched from a cursor or strongly typed cursor variable. In the illustration below, you declare two records. The first record stores a row selected from an emp table. The second record stores a row that is fetched from the cursor c1.DECLAREemp_rec emp%ROWTYPE;CURSOR c1 IS SELECT deptno, dname, loc FROM dept;dept_rec c1%ROWTYPE;The Columns in a row and corresponding fields in a record have the same names anddatatypes. Though, fields in a %ROWTYPE record do not inherit the NOT NULL column constraint.In the example below, you select column values into record emp_rec:BEGINSELECT * INTO emp_rec FROM emp WHERE...
Third Step at defining type SID in SQL CREATE DOMAIN SID AS VARCHAR(5) CHECK ( VALUE IS NOT NULL AND SUBSTRING(VALUE FROM 1 FOR 1) = 'S' AND CAST('+'||SUBSTRING(VALUE
Find the account numbers of all customers whose balance is more than 10,000 $
Varrays versus Nested Tables The Nested tables are differing from varrays in the following ways: 1) Varrays have a maximum size, while nested tables do not. 2) Varrays are
Understanding Varrays The Items of type VARRAY are termed as the varrays. They permit you to relate a single identifier with the whole collection. This relationship lets you man
Quantification in SQL To quantify something, as the theory book has it, is to state its quantity, to say how many of it there are. For example, in Tutorial D the expression CO
Consider the schema for FreeChecking Bank, that we designed given below. Translate the given ER schema into SQL CREATE TABLE statements (indicating primary key, unique and foreign
"Not Enforced" Table Constraints A constraint that is not enforced is not really a constraint within the meaning of the act, but SQL does have such a concept and it needs to b
Relational Operators The relational operators permit you to compare randomly complex expressions. The list below provides the meaning of each operator:
Example of Alternative formulation as a table constraint Example: Alternative formulation as a table constraint ALTER TABLE EXAM_MARK ADD CONSTRAINT Must_be_enrolled_to_
Biconditional - SQL The biconditional p ↔ q can be expressed in Tutorial D by p = q and the same is true of SQL. The question then arises as to whether, in SQL, p = q is equiv
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