Unix process api, Operating System

Assignment Help:

Unix process API

The two most important function calls to use when programming with several processes are fork and exec:

 fork() creates a copy of current process. It gives a different return value to each process and works based on Copy On Write;

 exec() replaces a process with an executable.

(The Windows CreateProcess(...), taking ten arguments, is analogous.)

Notice that fork() implies that each process descends from another process. In fact, in Unix everything descends from a single process called init: basically, init forks a process and then "replaces its code" with, say, the code of bash, using exec().

Example of how to use fork:
#include
#include
#include
int parentid = getpid();
char program_name[1024];
gets(program_name); // reads the name of program we want to start
int cid = fork();
if (cid==0) { // i'm the child
execlp(program_name, program_name, 0); // loads the program and runs it
printf("if the above worked, this line will never be reached\n");
}
else { // i'm the parent
sleep (1); // give my child time to start
waitpid(cid, 0, 0); // waits for my child to terminate
print("program %s finished\n", program_name);
}
Is the sleep(1) call necessary to allow the child process to start? The answer is no, it is not at all necessary. In general, if you think you need to sleep in a program, you are probably doing something wrong, and just slowing down your program. The call to waitpid() is a blocking wait, and will ?rst wait to let the child process start (if it hasn't already), then will wait until it ends.


Related Discussions:- Unix process api

Deadlock involving only one single process, Is it probable to have a deadlo...

Is it probable to have a deadlock involving only one single process? Describe your answer. Answer: No This pursue directly from the hold-and-wait condition.

Define segmentation, Define Segmentation  The memory allocation method...

Define Segmentation  The memory allocation method subject to “external” fragmentation is Segmentation.

Unsafe state in a deadlock-avoidance system, Question: A set of process...

Question: A set of processes are in a deadlock state when every process in the set is waiting for an event that can be caused by only another process in the set. (a) There

Explain about operating system services, Q. Explain about Operating System ...

Q. Explain about Operating System Services? An operating system offers services to programs and to users of those programs. It provided by one environment for execution of

How many disk operations are needed to fetch the i-node, How many disk oper...

How many disk operations are needed to fetch the i-node for the file /usr/ast/courses/os/handout.t? Assume that the i-node for the root directory is in memory, but nothing else alo

How can the deadlock be prevented-safe state, How can the deadlock be preve...

How can the deadlock be prevented-Safe State Safe state : A state is safe if the system is able to allocate resources to each process in some order and still avoid deadlock.

Explain what is file structure, Problem 1. List out the conditions that...

Problem 1. List out the conditions that result in Deadlock situations. Illustrate deadlock situation with a simple graphical notation Listing conditions for deadlock occu

What is a pure demand paging, What is a pure demand paging? When starti...

What is a pure demand paging? When starting implementation of a process with no pages in memory, the operating system sets the instruction pointer to the first instruction of t

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd