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Unit circle
A circle centered at the origin with radius 1 (i.e. this circle) is called as unit circle. The unit circle is very useful in Trigonometry.
(b) x2+ ( y - 3)2 = 4
In this part, it looks as the x coordinate of the center is zero as with the earlier part. However, this time there is something more with the y term and thus comparing this term to the standard form of the circle we can see that the y coordinate of the center have to be 3. The center & radius of this circle is then,
center = (0, 3) radius = √4 = 2
Following is a sketch of the circle. The center is marked alongwith a red cross in this graph.
A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii)
Differentiation Formulas : We will begin this section with some basic properties and formulas. We will give the properties & formulas in this section in both "prime" notation &
Consider the given graph G below. Find δ( G )=_____ , λ( G )= _____ , κ( G )= _____, number of edge-disjoint AF -paths=_____ , and number of vertex-disjoint AF -paths= ______
Computation method Whereas L = Lower class boundary of the class having the mode f 0 = Frequency of the class below the modal class
Evaluate the given limits, showing all working: Using first principles (i.e. the method used in Example 1, Washington 2009, Using definition to find derivative ) find the
Series - Special Series In this part we are going to take a concise look at three special series. In fact, special may not be the correct term. All three have been named th
how to explain this strategy? how to do this strategy in solving a problem? can you give some example on how to solve this kind of strategy.
construct the green''s function that satisfies dG''''-(2x+1)G''+(x+1)G=delta(x-s), G(0,s)=G(1,s)=0
Determine the linear approximation for f(x)= sin delta at delta =0
Find the 20 th term from the end of the AP 3, 8, 13........253. Ans: 3, 8, 13 .............. 253 Last term = 253 a20 from end = l - (n-1)d 253 - ( 20-1) 5 253
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