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Unit circle
A circle centered at the origin with radius 1 (i.e. this circle) is called as unit circle. The unit circle is very useful in Trigonometry.
(b) x2+ ( y - 3)2 = 4
In this part, it looks as the x coordinate of the center is zero as with the earlier part. However, this time there is something more with the y term and thus comparing this term to the standard form of the circle we can see that the y coordinate of the center have to be 3. The center & radius of this circle is then,
center = (0, 3) radius = √4 = 2
Following is a sketch of the circle. The center is marked alongwith a red cross in this graph.
sin10+sin20+sin30+....+sin360=0 sin10+sin20+sin30+sin40+...sin180+sin(360-170)+......+sin(360-40)+sin(360-30)+sin(360-20)+sin360-10)+sin360 sin360-x=-sinx hence all terms cancel
how do you find the tan, sin, and cos.
If two zeros of the polynomial f(x) = x 4 - 6x 3 - 26x 2 + 138x - 35 are 2 ± √3.Find the other zeros. (Ans:7, -5) Ans : Let the two zeros are 2 +√3 and 2 - √3 Sum of
Power rule: d(x n )/dx = nx n-1 There are really three proofs which we can provide here and we are going to suffer all three here therefore you can notice all of them. T
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Evaluate the mean of temperatures: Example: Given the subsequent temperature readings, 573, 573, 574, 574, 574, 574, 575, 575, 575, 575, 575, 576, 576, 576, 578 So
how to solve imaginary number such as like (-3v-5)² ?? Can I cancel the radical sign and the power of two ? and square the -3 and times to -5 ? hope you will answer this :) thanks
simple shapes
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