Unconditional and conditional probability, Mathematics

Assignment Help:

Independent and Dependent Events

Two events A and B are independent events if the occurrence of event A is in no way related to the occurrence or non-occurrence of event B. Likewise for independent events, the occurrence of event B is in no way related to the occurrence of event A.

Two events A and B are dependent events if the occurrence of one event say A is related to the occurrence of another event, say B.

MULTIPLICATION RULE: INDEPENDENT EVENTS

The joint probability of two outcomes that are independent is equal to the probability of the first outcome multiplied by the probability of the second outcome (the second outcome may be occurring simultaneously or some time in future), i.e. joint probability of two independent events is equal to the product of their marginal probabilities.

P(A and B) = P(A) . P(B) 


Related Discussions:- Unconditional and conditional probability

Age problem, three years ago,Rica was thrice as old as dandy.Three years he...

three years ago,Rica was thrice as old as dandy.Three years hence,she will be twice as old.Find their present.

Solving trig equations, Solving Trig Equations : Here we will discuss on s...

Solving Trig Equations : Here we will discuss on solving trig equations. It is something which you will be asked to do on a fairly regular basis in my class. Let's just see the

Complex numbers from the eigenvector and the eigenvalue, Complex numbers fr...

Complex numbers from the eigenvector and the eigenvalue. Example1 : Solve the following IVP. We first require the eigenvalues and eigenvectors for the given matrix.

Proof of constant times a function, Proof of Constant Times a Function: ...

Proof of Constant Times a Function: (cf(x))′ = cf ′(x) It is very easy property to prove using the definition given you a recall, we can factor a constant out of a limit. No

Prove the boolean expression, Prove the subsequent Boolean expression: ...

Prove the subsequent Boolean expression: (x∨y) ∧ (x∨~y) ∧ (~x∨z) = x∧z Ans: In the following expression, LHS is equal to:   (x∨y)∧(x∨ ~y)∧(~x ∨ z) = [x∧(x∨ ~y)] ∨ [y∧(x∨

Decimals, 2.46825141458*1456814314.446825558556

2.46825141458*1456814314.446825558556

Circles, alternate segment theorum

alternate segment theorum

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd