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Type of Microprocessor :
Microprocessors fall into 3 categories:
The general purpose microprocessor have ALU with 1 or more then 1 registers which functioned as, a control unit, accumulator ,an instruction decoder which handled a fixed instruction set special and general purpose registers which varied significantly from microprocessor to microprocessor. A microprocessor can have an internal stack of fixed length or use external memory for stack. The general purpose microprocessor is available of word lengths of 16, 32, 16, 8, 4, and 1 bit.
The Bit slice microprocessor divide the functions of ALL, special purpose and general purpose registers and control unit into many ICs. For this ALU and general purpose registers were packed in separately from controls. Each register of ALU (RALU) package was really equivalent to 2 or 4-bit wide slice of registers and the ALU of the microprocessor. Bit slice processor might be cascaded to produce any unconventional or conventional word length of the microprocessor such as 4, 8, 10, 12, 16, 32 or higher bits. The control portion of bit slice processor was constructed from microprocessor sequencer IC and other logics.
SHORT : The SHORT operator denoted to the assembler that only one byte is needed to code the displacement for a jump (for example displacement is within -128 to +127 bytes fr
Write a procedure to read a text file and copy its contents to another text file using 8086 assembly language .
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DMA Hardware (8237 DMAC) : 1)Processor contain HOLD/HOLD Acknowledge lines to interact with 8237 o DMAC can achieve control of ISA bus by asserting HOLD o P
Write a program that defines symbolic constants for all of the days of the week
wap proram for bthe addition of two 3*3 matrix
IInd Generation Microprocessor : The second generation microprocessor by using n MOS technology seemed in the market in 1973. The Intel 8080, of nMOS technology
I need to estimate the value of a definite integral using Riemann Sums and For our estimation let f(x) = x2 ,a=0, b=10 and n=5. Where a is the lower bound, b is the upper bound and
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Write an account of your findings and produce a report containing all aspects of the above. Include a step-by-step 'simple User Guide' so that your program can be operated as inten
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