Two-or-three-dimensional-motion, Physics

Assignment Help:

Net force acting on particle of mass 2 kg is 10N in north direction.At t=o, particle was moving eastwards with 10m/s. Find displacement and velocity of particle after 2 seconds.

Solution) given force =F=10N

mass M=2kg

velocity u=10m/s

then acceleration a=F/M=10/2=5m/s^2

then displacement=s=ut+1/2at^2

here u=initial velocity

t=time

a=acceleration

then we get the displacement is=30m

2.velocity=u+at

then we get velocity as 20m/s.

 


Related Discussions:- Two-or-three-dimensional-motion

Significance of quasi-fermi level with aid of band diagram, Significance of...

Significance of Quasi-Fermi Level with Aid of Band Diagram (a) Explain with diagrams different types of trap assisted generation and recombination. (b) Explain the signific

Explain the compton effect and its physical significance, Consider a partic...

Consider a particle of energy E is incident from the left on a rectangular potential barrier of height and width and on both sides of this barrier at which means that no force act

Relation between linear and angular variable, what is the relation between...

what is the relation between linear and angular variable?

Find the tension must this wire be stretched, A steel wire in a piano has a...

A steel wire in a piano has a length of 0.6000 m and a mass of 3.600   10 -3  kg. To what tension must this wire be stretched in order that the fundamental vibration correspond to

LASERS, What are different pumping mechanisms in LASERS?

What are different pumping mechanisms in LASERS?

What is index fiber, What is index fiber? How you define the modes in an op...

What is index fiber? How you define the modes in an optical fiber? Give a relation between core diameter and numerical aperture. Ans.:  The index profile of a single mode fi

Grating, what is plane diffraction grating?

what is plane diffraction grating?

3/9/2013 6:46:23 AM

Initial velocity is 10 m/s in x-direction.

Now a force of 10N acts in y-direction 

So , using F = ma 

               a = f/m = 10/2 = 5m/s2in y-direction 

After 2 seconds velocity in y-direction would become 10 m/s

Now we can take the resultant of the two velocities i.e 10 m/s in x-direction & 10m/s in y-direction

Therefore Resultant velocity = (102+102)1/2

                                        = (200)1/2 and 450 North of East

Displacement = velocity x time 

                    = (200)1/2x 2

                    = 20x(2)1/2m 450 north of east

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd