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Two circles touch internally at a point P and from a point T on the common tangent at P, tangent segments TQ and TR are drawn to the two circles. Prove that TQ = TR.
Given: Two circles touch each other internally at P . From a point T on the common tangent, tanget segments TQ and TR drawn to the two circles.
To prove : TQ = TRProof : TR = TP -------→ (1)
(Tangets from an external point are equal)Similarly, TQ = TP-------→(2)From (1)and (2), we get: TQ = TR
we know that log1 to any base =0 take antilog threfore a 0 =1
pendaraban dan
a²+b²=1 a+b
Two circles touch each other externally: Given: Two circles with respective centres C1 and C2 touch each other externaly at the point P. T is any point on the common tangent
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