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Two circles touch internally at a point P and from a point T on the common tangent at P, tangent segments TQ and TR are drawn to the two circles. Prove that TQ = TR.
Given: Two circles touch each other internally at P . From a point T on the common tangent, tanget segments TQ and TR drawn to the two circles.
To prove : TQ = TRProof : TR = TP -------→ (1)
(Tangets from an external point are equal)Similarly, TQ = TP-------→(2)From (1)and (2), we get: TQ = TR
Ut=Uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0 u(1,t)=-A/b^2 exp(-b)
mean absolue deviation
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