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Two circles touch internally at a point P and from a point T on the common tangent at P, tangent segments TQ and TR are drawn to the two circles. Prove that TQ = TR.
Given: Two circles touch each other internally at P . From a point T on the common tangent, tanget segments TQ and TR drawn to the two circles.
To prove : TQ = TRProof : TR = TP -------→ (1)
(Tangets from an external point are equal)Similarly, TQ = TP-------→(2)From (1)and (2), we get: TQ = TR
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It is not the first time that we've looked this topic. We also considered linear independence and linear dependence back while we were looking at second order differential equation
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