True inequality, Algebra

Assignment Help:

We have to give one last note on interval notation before moving on to solving inequalities. Always recall that while we are writing down an interval notation for inequality that the number onto the left has to be the smaller of the two.

Now it's time to begin thinking about solving linear inequalities. We will employ the following set of facts in our solving of inequalities.  Note down that the facts are given for <. However we can write down an equivalent set of facts for the remaining three inequalities.

1.   If a < b  then a + c < b + c and a - c < b - c for any number c.  In other term, we can add or subtract a number to both of sides of the inequality & we don't vary the inequality itself.

2.   If a < b and c > 0 then ac

3.   If a < b and c<0 then ac > bc  and a/c >   b/c .  In this case, unlike the earlier fact, if c is negative we have to flip the direction of the inequality while we multiply or divide both sides by the inequality through c.

These are closely the similar facts that we utilized to solve linear equations. The single real exception is the third fact. It is the important issue as it is frequently the most misused and/or forgotten fact in solving inequalities.

If you aren't certain that you believe that the sign of c matters for the second & third fact assume the following number instance.

                                                                   -3 < 5

This is a true inequality.  Now multiply both of sides by 2 and by -2.

- 3 < 5                                                                         - 3 < 5

-3( 2) < 5 ( 2)                                                             -3 ( -2) < 5 ( -2)

- 6 < 10                                                                         6 < -10

Sure enough, while multiplying by a +ve number the direction of the inequality remains the similar, however while multiplying by a -ve number the direction of the inequality does change.


Related Discussions:- True inequality

Homework, will you guys help mw with my homework?

will you guys help mw with my homework?

About rings, Prove that cosets of an ideal I in a ring R are disjoint or eq...

Prove that cosets of an ideal I in a ring R are disjoint or equal

Solving Absolute Value Equations, When is a problem an empty set and when d...

When is a problem an empty set and when do you have to solve for two problems when doing an equation?

Augmented matrices, In this section we have to take a look at the third met...

In this section we have to take a look at the third method for solving out systems of equations.  For systems of two equations it is possibly a little more complex than the methods

Solve the given log function, Example: Solve following equations. 2 log...

Example: Solve following equations. 2 log 9 (√x) - log 9 (6x -1) = 0 Solution  Along with this equation there are two logarithms only in the equation thus it's easy t

Functions, I am trying to figure out this answer f(x) = -3/4x + 4. but thi...

I am trying to figure out this answer f(x) = -3/4x + 4. but think I am getting it all wrong

Factor theorem, Factor Theorem For the polynomial P ( x ) , 1. If va...

Factor Theorem For the polynomial P ( x ) , 1. If value of r is a zero of P ( x ) then x - r will be a factor of P ( x ) . 2. If x - r is a factor of P ( x ) then r will

Operations of Functions, Use (fog)(4), (gof)(4), (fog)(x), and (gof)(x) 1.)...

Use (fog)(4), (gof)(4), (fog)(x), and (gof)(x) 1.) f(x)=x^2+1 and g(x)=x+5

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd