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Q. What do you understand by the tree traversal? Write down the procedure for traversing a binary tree in preorder and execute it on the following tree.
Ans:
The algorithm walks through tree data structure and performs some calculation at each node in the tree. This procedure of walking through the tree is called a tree traversal.
There are basically two different methods in which to visit systematically all the nodes of a tree-the depth-first traversal and the breadth-first traversal. Certain depth- first traversal methods happen frequently enough that they are given names of their own: preorder traversal, inorder traversal and postorder traversal.
The algorithm for traversing a tree in preorder is written as follows:-
i. Process the root R.
ii. Traverse left sub tree of R in preorder. iii. Traverse right sub tree of R in preorder. The preorder for the given tree is as follows:-
A L1 R1
A B L1l L1R R1
A B D L1R R1
A B D E R1
A B D E C R1L R1R
A B D E C F R1R
A B D E C F G
Suppose we have a set of N agents and a set of N tasks.Each agent can only perform exactly one task and there is a cost associated with each assignment. We would like to find out a
explain quick sort algorithm
Exact analysis of insertion sort: Let us assume the following pseudocode to analyse the exact runtime complexity of insertion sort. T j is the time taken to execute the s
The best average behaviour is shown by Quick Sort
The searching technique that takes O (1) time to find a data is Hashing is used to find a data
Q. Convert the given infix expression into the postfix expression (also Show the steps) A ∗ (B + D)/ E - F(G + H / k ) Ans. Steps showing Infix to Post fix
that will determine the volume of the sphere or the volume of cone or volume of pyramid depending on the choice of the user
Define the term - Array A fixed length, ordered collection of values of same type stored in contiguous memory locations; collection may be ordered in several dimensions.
24 56 47 35 10 90 82 31
Write an algorithm for binary search. Algorithm for Binary Search 1. if (low> high) 2. return (-1) 3. Mid = (low + high)/2 4. if ( X = = a[mid]) 5. return (mid); 6.
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