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Consider the task of identifying a 1 cm thick breast cancer that is embedded inside a 4.2 cm thick fibroglandular breast as depicted in Fig.
The cancerous tumor has a cross-sectional area of A=1 mm . Let us assume the beam is monoenergetic with photons of energy 20 keV. The total linear attenuation coefficients for the breast cancer and fibroglandular breast tissue at 20 keV are respectively µcancer=0.844 cm-1 and µfibroglandular=0.802 cm-1. First let's consider the case with no scatter at image receptor. Calculate the local radiographic contrast [i.e. C=|Nt-Nb|/Nb] for this particular imaging task.
Next, suppose that there was a constant S/P = 3 at the image receptor. Calculate the local radiographic constrast as in I but now including the scatter contribution.
The following relation is not a function. {(6,10) ( -7, 3) (0, 4) (6, -4)} Solution Don't worry regarding where this relation came from. It is only on
A group of 120 men had food for 200 days.After 5 days , 30 men die of disease.How long will the remaining food last
there are 5 small cubes and it reads the 5 small cubes is 1/100, then what is the ONE?
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how to find the minimum distance between any two particles which are in relative motion?
In a two dimensional case, the form of the linear function can be obtained if we know the co-ordinates of two points on the straight line. Suppose x' and x" are two
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a deposit of 10,000 was made to an account the year you were born after 12 years the account is worth 16,600 what is the simple interest rate did the account earn?
find h in the parallelogram
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