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Consider the task of identifying a 1 cm thick breast cancer that is embedded inside a 4.2 cm thick fibroglandular breast as depicted in Fig.
The cancerous tumor has a cross-sectional area of A=1 mm . Let us assume the beam is monoenergetic with photons of energy 20 keV. The total linear attenuation coefficients for the breast cancer and fibroglandular breast tissue at 20 keV are respectively µcancer=0.844 cm-1 and µfibroglandular=0.802 cm-1. First let's consider the case with no scatter at image receptor. Calculate the local radiographic contrast [i.e. C=|Nt-Nb|/Nb] for this particular imaging task.
Next, suppose that there was a constant S/P = 3 at the image receptor. Calculate the local radiographic constrast as in I but now including the scatter contribution.
calculation of emi %
EVERY TIME I TRY TO DO ANY KIND OF FRACTIONS WELL MULTIPLYING I ALWAYS GET IT WRONG
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1/2+3/4
The Definition of the Derivative : In the previous section we saw that the calculation of the slope of a tangent line, the instantaneous rate of change of a function, and the ins
how to find x,y and z in parallelograms,rhombus etc.
Average cost function : Now let's turn our attention to the average cost function. If C ( x ) is the cost function for some of the item then the average cost function is,
how to find basic intrest problems
1/2+1/2
compare: 643,251: 633,512: 633,893. The answer is 633,512.
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