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Consider the task of identifying a 1 cm thick breast cancer that is embedded inside a 4.2 cm thick fibroglandular breast as depicted in Fig.
The cancerous tumor has a cross-sectional area of A=1 mm . Let us assume the beam is monoenergetic with photons of energy 20 keV. The total linear attenuation coefficients for the breast cancer and fibroglandular breast tissue at 20 keV are respectively µcancer=0.844 cm-1 and µfibroglandular=0.802 cm-1. First let's consider the case with no scatter at image receptor. Calculate the local radiographic contrast [i.e. C=|Nt-Nb|/Nb] for this particular imaging task.
Next, suppose that there was a constant S/P = 3 at the image receptor. Calculate the local radiographic constrast as in I but now including the scatter contribution.
Topic : Use of Electronic whiteboards (ICT) in primary education in Australia and international. What are the key theories, concepts and ideas related to your topic? Wha
Sir, With due respect,I, beg to state that I want to join as a maths expert and earn some money. I would be grateful to you if you guide me in this regard.
1+1
Now we have to start looking at more complicated exponents. In this section we are going to be evaluating rational exponents. i.e. exponents in the form
Consider a class of 55 students. The student names are placed in a hat & 3 names are randomly drawn without replacement. a) If the first person drawn was named the class presi
I need help solving this question...You have to design a rectangular flyer. The top and bottom must have 5" margins and the left and right sides must have 2" margins. If you must
The cost of renting a bike at the local bike shop can be represented through the equation y = 2x + 2, where y is the total cost and x is the number of hours the bike is rented. Whi
p1(-3,-1),p2(9,4)
What percent of the figure below is shaded? Break the rectangle into eighths as shown below. The shaded part is 6/8 or 3/4 ; 3/4 is 75%.
Which of the following sets are equal? S 1 = {1, 2, 2, 3}, S 2 = {x | x 2 - 2x + 1 = 0}, S 3 = {1, 2, 3}, S 4 = {x | x 3 - 6x
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