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Consider the task of identifying a 1 cm thick breast cancer that is embedded inside a 4.2 cm thick fibroglandular breast as depicted in Fig.
The cancerous tumor has a cross-sectional area of A=1 mm . Let us assume the beam is monoenergetic with photons of energy 20 keV. The total linear attenuation coefficients for the breast cancer and fibroglandular breast tissue at 20 keV are respectively µcancer=0.844 cm-1 and µfibroglandular=0.802 cm-1. First let's consider the case with no scatter at image receptor. Calculate the local radiographic contrast [i.e. C=|Nt-Nb|/Nb] for this particular imaging task.
Next, suppose that there was a constant S/P = 3 at the image receptor. Calculate the local radiographic constrast as in I but now including the scatter contribution.
Two angles are supplementary. The evaluate of one is 30 more than twice the measure of the other. Determine the measure of the larger angle. a. 130° b. 20° c. 50° d. 70
in the quadrilateral abcd,ab is 4.3,bd is 5.1,ad is 4.8.angle bdc is 20 degrees and angle c is 80 degrees.all dimentions in metres.calculate the unknown sides and angles of the plo
Sketch the graph of y = ( x -1) 2 - 4 . Solution Now, it is a parabola .Though, we haven't gotten that far yet and thus we will have to select
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two colum proofs
Patio measures 24 meters square. Patio stone are 30 cm each side. How many stones are required to cover the patio?
Reason for why limits not existing : In the previous section we saw two limits that did not. We saw that did not exist since the function did not settle down to a sing
how can i use unit of measurement
find the simple interest on Rs. 68,000 at 50/3 per annum for 9 month
how to find out percentage error?
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