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From top of a tower a stone is thrown up and it reaches the ground in time t1. A second stone is thrown down with the same speed and it reaches the ground in t2. A third stone is released from rest and it reaches the ground in time t3 then t3= ?solution)
let the intial speed be ''u'' and height be ''h''.
h(-j)=u(j)*t1+0.5g(-j)*t12
Case(2)
h(-j)=u(-j)*t2+0.5g(-j)*t22
Case(3)
h(-j)=0.5g(-j)*t32
solve case 1 and case 2 for t1 and t2 (quadratic) .
what difference between these two laws
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Explain the Air Resistance If you drop a feather and a cannonball at the same time from the same height, which will hit the ground first? The cannonball of course. Why does the
its very easy quest. we just need to find the values in u,g,and v(final velocity,this is constant for the first two cases) for first throw. t1= 2u/g + v-u/g=v+u/g for second throw. t2=v-u/g for third release. t3=u/g so t3=(t1-t2)/2g
its very easy quest. we just need to find the values in u,g,and v(final velocity,this is constant for the first two cases)
for first throw.
t1= 2u/g + v-u/g=v+u/g
for second throw.
t2=v-u/g
for third release.
t3=u/g
so t3=(t1-t2)/2g
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