#title.MODI method, C/C++ Programming

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How does c++ help with the tradeoff of security vs.usability, A: In C, enca...

A: In C, encapsulation was completed by making things static in a compilation unit or module. It prevented another module from accessing the static stuff. (Incidentally, now static

Minimum shelf, At a shop of marbles, packs of marbles are prepared. Packets...

At a shop of marbles, packs of marbles are prepared. Packets are named A, B, C, D, E …….. All packets are kept in a VERTICAL SHELF in random order. Any numbers of packets with thes

If else, A small shop sells 280 different items. Every item is identified b...

A small shop sells 280 different items. Every item is identified by a 3 - digit code. All items which start with a zero (0) are cards, all items which start with a one (1) are swee

Expression, i need expression and its types with example programs in c++

i need expression and its types with example programs in c++

Stream input and output functions, Within C we access external devices by ...

Within C we access external devices by means of a pointer i.e. address. The address could point to any memory mapped device i.e. Ram, Rom, Duart, Disk drives etc. Therefore there i

E^x, Write a program to calculate e^x using the formula: e^x = 1 + x/1! + ...

Write a program to calculate e^x using the formula: e^x = 1 + x/1! + x^2/2! + x^3/3! + ...... Allow the user to enter the integer number x, then do the calculation in a loop (for

Develop online slot video game for facebook, Develop Online Slot Video Game...

Develop Online Slot Video Game for Facebook Prepare an online slot video game for a Facebook promotion in order to draw new visits and Increase the number of "likes" of the Face

#padovan string, program that counts the number of occurrences of the strin...

program that counts the number of occurrences of the string in the n-th padovan string p(n)

Padovan String, A Padovan string P(n) for a natural number n is defined as:...

A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of t

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