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Surface Area- Applications of integrals In this part we are going to look again at solids of revolution. We very firstly looked at them back in Calculus I while we found the
Short Cuts for solving quadratic equations
Eliminate the parameter from the subsequent set of parametric equations. X = t 2 + t Y = 2t - 1 Solution: One of the very easy ways to eliminate the parameter is to
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Given So calculate AB. Solution The new matrix will contain size 2 x 4. The entry in row 1 and column 1 of the new matrix will be determined by multiplying row 1 of
The line 4x-3y=-12 is tangent at the point (-3,0) and the line 3x+4y=16 is tangent at the point (4,1). find the equation of the circle. solution) well you could first find the ra
Sin3x ? Solution) THE FORMULA IS RIGHT ,SO sin3x=3sinx-4sin 3 x
solve the differential equation 8yk+2-6yk+1+yk=9 ,k=0 given that Y0=1 and y1=3/2
all perimeter and area
A car travels 283 1/km in 4 2/3 hours .How far does it go in 1 hour?
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