integration, Mathematics

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If p=10 when q=2,find p when q=5

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Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C.  Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0

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A function is a relation for which each of the value from the set the first components of the ordered pairs is related with exactly one value from the set of second components of t

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