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Multiply 2(b + 5)
In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to exami
2(5+6csquared)-30divided by 3 c=2 d=4
how many car washes can you get at the has station and still pay less than 32.99 if the local gas station is 10.95 plus tax
To this instance in this chapter we've concentrated on solving out equations. Now it is time to switch gears a little & begin thinking regarding solving inequalities. Before we g
Example Solve each of the following systems of equations. 5x + 4 y = 1 3x - 6 y = 2 Solution It is the system in the previous examples wh
We'll begin this section by defining just what a root or zero of a polynomial is. We say that x = r is a root or zero of a polynomial, P ( x) , if P ( r )= 0 . In other terms x=
Now it is time to look at solving some more hard inequalities. In this section we will be solving (single) inequalities which involve polynomials of degree at least two. Or, to p
5(4a+1)+6=-(-11a+1)+6a
Prove that cosets of an ideal I in a ring R are disjoint or equal
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