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limit 0 to 2(3x^2+2) Solution) integrate 3x^2 to x^3 and 2 to 2x and apply the limit from 0 to 2 answer is 12.
http://www.idea.wsu.edu/Range/
Show that the product of 3 consecutive positive integers is divisible by 6. Ans: n,n+1,n+2 be three consecutive positive integers We know that n is of the form 3q, 3q +1
i need help in math
The interval of validity for an IVP along with initial conditions: y(t 0 ) = y 0 or/and y (k) (t 0 ) = y k There is the largest possible interval on that the solution is va
y''''+6y''+10y=10x^(4)+24x^(3)+2x^(2)-12x+18
application of derivatives in engg.
sin10+sin20+sin30+....+sin360=0 sin10+sin20+sin30+sin40+...sin180+sin(360-170)+......+sin(360-40)+sin(360-30)+sin(360-20)+sin360-10)+sin360 sin360-x=-sinx hence all terms cancel
how to round off 42,999,523
In algebra knowing that 2 3 = 8 is not sufficient. Equally important to know is what would be the result if quantities like 2 3 . 2 -4 . 2 6 or 3 7 / 3 2
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