#title.fractions, Mathematics

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If tanA+sinA=m and tanA-sinA=n, show that m 2 -n 2 = 4√mn Ans:    TanA + SinA = m       TanA - SinA = n. m 2 -n 2 =4√mn . m 2 -n 2 = (TanA + SinA) 2 -(TanA - SinA) 2

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