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In the figure, ABCD is a square inside a circle with centre O. The Centre of the square coincides with O & the diagonal AC is horizontal of AP, DQ are vertical & AP = 45 cm, DQ = 2
Arc Length for Parametric Equations L = ∫ β α √ ((dx/dt) 2 + (dy/dt) 2 ) dt Note: that we could have utilized the second formula for ds above is we had supposed inste
51/6 divided by 31/3
If we "break up" the root into the total of two pieces clearly we get different answers. Simplified radical form: We will simplify radicals shortly so we have to next
Divides a given line-segment externally in the ratio of 1:2 Construction: i )Draw BX making an actueangle at B. ii) Starting from B, mark 2 equal points on BX as shown in the f
Need Solution Find (dy)/( dx) for; (i). y = x 7 (ii). y = x 2γ (iii). y = x -3 (iv). y = x
PROOF OF VARIOUS INTEGRAL FACTS/FORMULAS/PROPERTIES In this section we've found the proof of several of the properties we saw in the Integrals section and also a couple from t
Calculate the area and perimeter of a square: Calculate the area and perimeter of a square with w = 5´ and l = 6´. Be sure to involved units in your answer. Solution:
Perpendicular to the line given by 10 y + 3x= -2 For this part we desire the line to be perpendicular to 10 y + 3x= -2 & so we know we can determine the new slope as follows,
Describe and sketch the surfaces z + |y| = 1 and (x 2) 2 y + z 2 = 0.
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