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f(x)+f(x+1/2) =1 f(x)=1-f(x+1/2) 0∫2f(x)dx=0∫21-f(x+1/2)dx 0∫2f(x)dx=2-0∫2f(x+1/2)dx take (x+1/2)=v dx=dv 0∫2f(v)dv=2-0∫2f(v)dv 2(0∫2f(v)dv)=2 0∫2f(v)dv=1 0∫2f(x)dx=1
At rest, the human heart beats once every second. At the strongest part of the beat, a person's blood pressure peaks at 120mmHg. At the most relaxed part of the beat, a person's bl
Standard Basis Vectors Revisited In the preceding section we introduced the idea of standard basis vectors with no really discussing why they were significant. We can now do
Example1 : Solve the subsequent system of equations. -2x 1 + x 2 - x 3 = 4 x 1 + 2x 2 + 3x 3 = 13 3x 1 + x 3 = -1 Solution The initial step is to write d
Limits At Infinity, Part I : In the earlier section we saw limits which were infinity and now it's time to take a look at limits at infinity. Through limits at infinity we mean
For queries Q 1 and Q 2 , we say Q 1 is contained in Q 2 , denoted Q 1 ⊆ Q 2 , iff Q 1 (D) ⊆ Q 2 (D) for every database D. The container problem for a fixed Query Q 0 i
solving
show that the green''s function for x"=0,x(1)=0,x''(0)+x''(1)=0 is G(t,s)=1-s
Determine the slope following lines. Sketch the graph of line. The line which contains the two points (-2, -3) and (3, 1) . Solution we'll need to do is employ
In the riangle ABC the AB=12 cm,AC=28 cm and angle ABC=120 degrees.BC=?
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