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Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve betw
#include float start_point, /* GLOBAL VARIABLES */ end_point, total_area; int numtraps; main( ) { void input(void ); float find_area(float a,float b,int n); /* prototype */ print(“AREA UNDER A CURVE”); input( ); total_area = find_area(start_point, end_point, numtraps); printf(“TOTAL AREA = %f”, total_area); } void input(void ) { printf(“\n Enter lower limit:”); scanf(“%f”, &start_point); printf(“Enter upper limit:”); scanf(“%f”, &end_point); printf(“Enter number of trapezoids:”); scanf(“%d”, &numtraps); } float find_area(float a, float b, int n) { float base , lower, h1, h2; /* LOCAL VARIABLES */ float function_x(float x); /* prototype */ float trap_area(float h1,float h2,float base );/*prototype*/ base = (b-1)/n; lower = a; for (lower =a; lower <= b-base ; lower = lower + base ) { h1 = function_x(lower); h1 = function_x(lower + base ); total_area += trap_area(h1, h2, base ); } return (total_area); float trap_area(float height_1,float height_2,float base ) { float area; /* LOCAL VARIABLE */ area = 0.5 * (height_1 + height_2) * base ; return (area); } float function_x(float x) { /* F(X) = X * X + 1 */ return (x*x + 1); } Output AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 30 TOTAL AREA = 12.005000 AREA UNDER A CURVE Enter lower limit: 0 Enter upper limit: 3 Enter number of trapezoids: 100 TOTAL AREA = 12.000438
Designed, developed, tested and documented the demo created for NPBlox framework. NPBlox framework is a framework which enabled developers to create CLI/WEB/SNMP interfaces for
Ask qDiscuss the risks of having a single root user and how more limited management abilities can be given to others users on Linux/UNIX systems.uestion #Minimum 100 words accepted
SAP system configuration includes It includes :- a) Dialog tasks b) Update tasks.
Perform the - 48 - 23 operations using the 2's complement method. Ans. - 48 - 23 = - 48 + (-23) -48 = 1 1 0 1 0 0 0 0 -23 = 1 1 1 0 1 0 0 1 = -71
Typical human voice is centered around Hz. (A) 200-400 (B) 280-3000 (C) 400-600
Write a program to input an address i.e. 20 Hex and read the byte (char) contents of that address Answer include void main() { char prompt; Date: 26th August 2012
Each student will be assigned a binary system. The experimental references and the conditions are indicated in the table below. The student should make use of software available on
* Public, protected and private are 3 access specifier in C++. * Public data members and member functions are accessible outside the class. * Protected data members and memb
Q. What is Accumulator Register? Accumulator Register (AC): This register is used to store data temporarily for computation by Arithmetic and logic unit (ALU). AC generally c
Q. What is the dissimilarity between dynamic strain aging and strain aging? Answer:- Strain aging could be explains as "normal wear and tear" or the fatigue that is experi
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