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What is the integratin of 1/sin2x?, ∫1/sin2x dx = ∫cosec2x dx = 1/2 log[cos...

∫1/sin2x dx = ∫cosec2x dx = 1/2 log[cosec2x - cot2x] + c = 1/2 log[tan x] + c Detailed derivation of ∫cosec x dx = ∫cosec x(cosec x - cot x)/(cosec x - cot x) dx = ∫(cosec 2 x

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Methods for doing integral, There are really three various methods for doin...

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