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(y-3)=2(x +2)
a^4b+a^2b^3
I dont really understand it can you help me
Using transformation to sketch the graph f ( x ) = (x - 2) 2 + 4 Solution In this part it looks as the base function is x 2 and it looks a
how do I solve for a monomial?
Example: Solve following equations. 2 log 9 (√x) - log 9 (6x -1) = 0 Solution Along with this equation there are two logarithms only in the equation thus it's easy t
1/1+x+1/y+1/1+z+1/x+1/1+y+1/z=1
81x^5-49x^3=0
(3b+1)^2=16
I don''t understand it
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