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Q. Timing in MPI program?
MPI_Wtime ( ) returns lapsed wall clock time in seconds because some random point in past. Elapsed time for program section is given by difference between MPI_Wtime values at starting and end of process. Process clocks aren't necessarily synchronised, so clock values aren't necessarily comparable across the processes and care should be taken in determining overall running time for parallel program. Even if clocks are openly synchronised variation across clocks still can't be expected to be considerably less than round-trip time for zero-length message between the processes.
Give your analysis for the following problem statement: You require to write a program that calculates the area and perimeter of a rectangle whose dimensions (Length &width) are gi
The result of adding hexadecimal number A6 to 3A is ? Ans. The result will be E0.
Q. How to Correct the error condition while copying file in DOS? In most case, DOS allows you to correct the error condition and retry the command (by pressing R). If the drive
Features of MPI-1 Binding for FORTRAN and C Collective communication Communication domains and Process groups Point-to-point communication Virtual process
Define the Unified Modelling Language (UML) is used to express construct and relationships of complex systems. This was created in response to a request for proposal (RFP) fro
Q. Example to show directory in doc? Like a file name, the directory name may also have up to eight alpha-numeric characters. The directory name can also have an extension
Q. What is typical storage hierarchy? A typical storage hierarchy is displayed in Figure above. Though Figure shows only block diagram however it includes storage hierarchy:
What is virtual memory? Method that automatically move program and datablocks into the physical main memory when they are needed for execution are known as virtual memory.
what would be the occupancy of each leaf node of a B+ tree
Q. Prove using Boolean Algebra 1. AB + AC + BC' = AC + BC' 2. (A+B+C) (A+B'+C') (A+B+C') (A+B'+C)=A 3. (A+B) (A'+B'+C) + AB = A+B 4. A'C + A'B + AB'C + BC = C + A'B
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