Time slice, Computer Engineering

Assignment Help:

The Linux Process Scheduler uses time slice to prevent a single process from using the CPU for too long. A time slice specifies how long the process can use the CPU. In our simulation, the minimum time slice possible is 10ms and the maximum time slice possible is 300 ms. The scheduler assigns higher time slices to processes that are more interactive and lower time slices to processes that are more CPU intensive. Note that time slice is a positive integer in this range [10, 300]. To calculate the time slice, we use this formula:

2160_Time slice.png

Each process is supplied with a priority level that ranks a process based on their worth and need for processor time. The priority levels range from 100 to 140 [100,140]. Processes with a lower priority will run before a process with a higher priority. Process with a lower priority level also receives a longer time slice. A process's initial priority (sometimes called static priority) is calculated based on its nice value. Nice values range from -20 to +19 [-20, 19] indicating how nice the process is. Larger nice values correspond to a lower priority. CPU intensive processes typically have higher nice values while IO bound processes have lower nice values. Nice values are provided with the input file. Note that a priority value is a positive integer in this range

[100,140]. To calculate the initial (or static) priority we use this formula:

2269_Time slice1.png

After a process exhausts its time slice, it will join the expired queue or go back to the active queue. Before doing that, it has to calculate its new priority (sometimes called the dynamic priority). This is the formula used to calculate the dynamic priority:

priority = original priority + bonus:

865_Time slice2.png

Bonus points are given to processes that either use too much or too little CPU time. Bonus points are integers range from -5 to +5 ([-5, 5]). Here are the guidelines to calculating bonus points:

547_Time slice3.png

Note : Here total IO mean the total time spent in the IO queue to this point and total CPU mean the total time spent in the CPU to this point.


Related Discussions:- Time slice

Acting rationally - artificial intelligence, Acting Rationally: "Al" C...

Acting Rationally: "Al" Capone was finally convicted for tax evasion. Were the police reacting on rationally?? To solve this puzzle, we must first look at how the performance

Concurrently read concurrently write, Q. Concurrently read concurrently wri...

Q. Concurrently read concurrently write? It is one of the models derived from PRAM. In this model the processors access the memory locations simultaneously for reading and writ

Simplify the Boolean expression, The Boolean expression A‾.B + A.B‾ + A.B i...

The Boolean expression A‾.B + A.B‾ + A.B is equivalent to ? Ans. The Boolean expression A‾ .B + A. B‾+ A.B is equivalent to A + B (A‾ .B + A. B‾+ A.B = B( A‾ + A) + A. B‾ =

Register data type as sequential element, Reg data type as Sequential eleme...

Reg data type as Sequential element module reg_seq_example( clk, reset, d, q); input clk, reset, d; output q; reg q; wire clk, reset, d; always @ (posedge clk or

Define colspan and rowspan, Q. Define Colspan and Rowspan? Now let's se...

Q. Define Colspan and Rowspan? Now let's see how to work with COLSPAN (Column Span) and ROWSPAN (Row Span). If we want cell containing Ajay in Figure to be extended to the next

What is analysis iteration, Analysis Iteration   To understand any prob...

Analysis Iteration   To understand any problem completely you have to repeat task which implies that analysis requires repetition. First, just get overview of problem, make a r

How many two-input AND and OR gates are required to realize , How many two-...

How many two-input AND and OR gates are required to realize Y=CD+EF+G ? Ans. Y=CD+EF+G No. of two i/p AND gates=2 No. of two i/p OR gates = 2 One OR gate to OR CD and EF

What is called dhcp, DHCP stands for? DHCP that is stands for Dynamic H...

DHCP stands for? DHCP that is stands for Dynamic Host Configuration Protocol.

Explain about associative memory organisations, Q. Explain about Associativ...

Q. Explain about Associative Memory Organisations? The associative memory is arranged in w words with b bits per word. In w x b array, every bit is known as a cell. Every cell

Explain sequential sharing, Explain Sequential sharing. Sequential s...

Explain Sequential sharing. Sequential sharing: In this technique of sharing, a file can be shared through only one program at a time, it is file accesses by P1 and P2 are

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd