Tied rankings, Mathematics

Assignment Help:

Tied Rankings

A slight adjustment to the formula is made if several students tie and have the similar ranking the adjustment is:

(t3 - t)/12

Whereas t = number of tied rankings the adjusted formula becomes

R = 1 -

1002_Tied Rankings.png


Related Discussions:- Tied rankings

Net Present Value, A business has the opportunity to expand by purchasing ...

A business has the opportunity to expand by purchasing a machine at a cost of £80,000. The machine has an estimated life of 5 years and is projected to generate a cashflow of £20,0

Relative motion, how to find the minimum distance between any two particles...

how to find the minimum distance between any two particles which are in relative motion?

Size of the penumbra, With reference to Fig. 1(a) show that the magnificati...

With reference to Fig. 1(a) show that the magnification of an object is given by M=SID/SOD. With reference to Fig. 1(b) show that the size of the penumbra (blur) f is given by f

Multiplication of two like terms with opposite signs, The product of -7ab a...

The product of -7ab and +3ab is (-7 x 3) a 2  b 2  = -21a 2  b 2 . In other words, a term with minus sign when multiplied with a term having a positive sign, gives a product having

Math, what is quantity ?

what is quantity ?

BOUNDARY VALUE PROBLEM, Ut=Uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0...

Ut=Uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0 u(1,t)=-A/b^2 exp(-b)

Position vector - calculus, Position Vector There is one presentation o...

Position Vector There is one presentation of a vector that is unique in some way.  The presentation of the ¯v = (a 1 ,a 2 ,a 3 ) that begins at the point  A = (0,0,0) and ends

Find the equation of circle concentric – coordinate geometry, 1. A point P(...

1. A point P(a,b) becomes (3,c) after reflection in x - axis, and (d,6) after reflection in the origin. Show that a = 3, b = - 6, c = 6, d = 2 2. If the pair of lines ax² + 2pxy

Geometry , Solving for X in isosceles triangles

Solving for X in isosceles triangles

Find no. of non negative integral solutions, Find no. of non negative integ...

Find no. of non negative integral solutions x 1 +x 2 +x 3 +4x 4 =20 Solution)  140. Break them into prime factors . Put 4 = 2^2 and every variable will have factors in 2,3,5 with

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd