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Thin uniform wire bent - centre of gravity:
Find out the C. G. of the thin uniform wire bent into shape ABC as illustrated in Figure.
Solution
Assume G be the location of C. G. of the bar as illustrated in Figure
∴ L = L1 + L2 = 5 + 5 = 10 m (AB = L1; BC = L2)
Taking moments w.r.t. y-axis
L x¯ = L1 x1 + L2 x2 = 5 × 0 + 5 × 2 = 10
∴ x¯ = 1 m
Taking moments around x axis,
L y¯ = 5 × 2.5 + 5 × 6.5 = 5 × (2.5 + 6.5)
∴ y¯ = 4.5 m
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