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Calculate the free energy change of following reaction at298 kelvin H2+I2=2HI if the enthalpy change is 51.8816kj and the entropy change is 166.15j is this reaction thermodyanamically possible?
Solution) delta g=51.8816kj-298*166.15/1000kjdelta g=2.3689since delta g is +ve therefore this reaction is not themodynamically possible
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Free energy change=enthalpy change-298(entropy change) reaction is thermodynamically possible if free energy change is negative.
Free energy change=enthalpy change-298(entropy change)
reaction is thermodynamically possible if free energy change is negative.
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