Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Theorem
Consider the subsequent IVP.
y′ = p (t ) y = g (t )
y (t0)= y0
If p(t) and g(t) are continuous functions upon an open interval a < t < b and the interval includes to, after that there is a unique solution to the IVP on such interval.
Therefore, just what does this theorem tell us? Initially, it tells us that for nice adequate linear first order differential equations solutions are guaranteed to exist and more significantly the solution will be particular. We may not be capable to get the solution, but do identify that it exists and which there will only be one of them. It is the very significant aspect of this theorem. Identifying that a differential equation has a unique solution is probably more significant than actually having the solution itself!
Subsequently, if the interval in the theorem is the largest possible interval on that p(t) and g(t) are continuous so the interval is the interval of validity for the solution. This means that for linear first order differential equations, we won't want to actually solve the differential equation in order to get the interval of validity. See that the interval of validity will based only partially on the initial condition. The interval should hold to, but the value of yo, has no consequence on the interval of validity.
- Find the total surface area of a frustum of a cone. (Include top and bottom). The equation that I have for volume is v=1/3 pi x h(r^2+rR+R^2) -the equation that I have found fo
Lindsay purchased a pocketbook for $45 and a pair of shoes for $55. The sales tax on the items was 6%. How much sales tax did she pay? Find out the price of the two items toget
greens function for x''''=0, x(1)=0, x''(0)+x''(1)=0 is G(t,s)= {1-s for t or equal to s
ABCD is a rectangle. Δ ADE and Δ ABF are two triangles such that ∠E=∠F as shown in the figure. Prove that AD x AF=AE x AB. Ans: Consider Δ ADE and Δ ABF ∠D = ∠B
4 1/2 ----2----1/3=3
Solving an equation using Multiplication and Division A variable is a symbol that represents a number. Usually we use the letters like n , t , or x for variables. For
13 1/4 34 56/89
3x^2+19x-14=0
a deposit of 10,000 was made to an account the year you were born after 12 years the account is worth 16,600 what is the simple interest rate did the account earn?
Example of division of fractions: Example: (4/5)/(2/9) = Solution: Step 1: Invert the divisor fraction (2/9) to (9/2). Step 2: Multip
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd