Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Theorem
Consider the subsequent IVP.
y′ = p (t ) y = g (t )
y (t0)= y0
If p(t) and g(t) are continuous functions upon an open interval a < t < b and the interval includes to, after that there is a unique solution to the IVP on such interval.
Therefore, just what does this theorem tell us? Initially, it tells us that for nice adequate linear first order differential equations solutions are guaranteed to exist and more significantly the solution will be particular. We may not be capable to get the solution, but do identify that it exists and which there will only be one of them. It is the very significant aspect of this theorem. Identifying that a differential equation has a unique solution is probably more significant than actually having the solution itself!
Subsequently, if the interval in the theorem is the largest possible interval on that p(t) and g(t) are continuous so the interval is the interval of validity for the solution. This means that for linear first order differential equations, we won't want to actually solve the differential equation in order to get the interval of validity. See that the interval of validity will based only partially on the initial condition. The interval should hold to, but the value of yo, has no consequence on the interval of validity.
Graph for the Sequence First we wish to think about the term graphing a sequence. To graph the sequence {a n } we plot the points {n, a n } as n ranges over every possible valu
DECISION TREE ANALYSIS The Finance Manager of ‘Softy’ baby soap manufacturing company being successful in the first two years of the company’s operations is considering to set
Show that of all right triangles inscribed in a circle, the triangle with maximum perimeter is isosceles.
If the diameter of a circle is tripled times, the circumference is a. multiplied by 3. b. multiplied by 6. c. multiplied by 9. d. multiplied by 12. a. The formula fo
what is prime factorization of 200
How do you find the second minimum spanning tree of a graph? Find the second minimum spanning tree of the following graph. Ans: The second minimum spanning tree is acq
#questionShow that the system oscillates in simple harmonic motion demonstrated by; , for which the general solution where X = (x – x0)..
One integer is two more than another. The sum of the lesser integer and double the greater is 7. What is the greater integer? Let x = the greater integer and y = the lesser int
ogive for greater than &less than curves
how to divide an arc in three equal parts
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd